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3 years ago

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Describe the type of energy transfers that occur in photosynthesis

1 answer:

Alexeev081 [22]3 years ago

4 0

Answer:

light energy transfers electrons from water (H 2 O) to carbon dioxide (CO 2), to produce carbohydrates. In this transfer, the CO 2 is "reduced," or receives electrons, and the water becomes "oxidized," or loses electrons

Explanation:

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According to kinetic theory, which two factors are important for a successful reaction to occur?

fgiga [73]

Answer:

Molecules must collide with sufficient energy, known as the activation energy, so that chemical bonds can break. Molecules must collide with the proper orientation.

Explanation:

A collision that meets these two criteria, and that results in a chemical reaction, is known as a successful collision or an effective collision.

6 0

2 years ago

A train travels 72 kilometers in 1 hours, and then 64 kilometers in 1 hours. What is its average speed?

garri49 [273]

To find the average of something you must first add everything together and then divide it by the total amount of numbers you added together.

First add 72 and 64 together

72+64=136

Now divide 136 by 2

136/2=68

So the average speed of the train is 68 kilometers

5 0

3 years ago

Using a pulley system, Adam lifts a 400 kg load by putting an effort for 80 kg. How many pulley s are there in the system?

motikmotik

288282828 393993939292

3 0

3 years ago

an object is moving forward with a constant velocity. which statement about this object must be true?

love history [14]

Answer:

• Its acceleration is zero

Explanation:

from definition of acceleration:

${ \rm{acceleration = \frac{change \: in \: velocity}{time} }} \\ \\ { \rm{acceleration = \frac{ \delta \: (velocity)}{time} }}$

• since velocity is constant, change in velocity is zero

${ \boxed{ \rm{ \delta \: (velocity) = 0}}}$

• therefore:

${ \rm{acceleration = \frac{0}{time} }} \\ \\ { \boxed{ \tt{acceleration = 0 \: m {s}^{ - 2} }}}$

4 0

3 years ago

I can’t figure this out!!! Answer what you can , please.

tigry1 [53]

a/b. The ball has velocity vector at time $t$

$\vec v=(v_x,v_y)=(v_0\cos63^\circ,v_0\sin63^\circ-gt)$

where $v_0=16\dfrac{\rm m}{\rm s}$ is the ball's initial speed and $g=9.8\dfrac{\rm m}{\mathrm s^2}$ .

c. At its highest point, the ball has 0 vertical speed. This occurs when

$v_0\sin63^\circ-gt=0\implies t=1.5\,\mathrm s$

d. Recall that

${v_y}^2-{v_{0y}}^2=-2g\Delta y$

so that at its highest point,

$0^2-(v_0\sin63^\circ)^2=-2g\Delta y\implies\Delta y=10\,\mathrm m$

e. This is just twice the time it takes for the ball to reach its maximum height, $t=2.9\,\mathrm s$ .

f. The ball's horizontal position after time $t$ is

$v_0\cos63^\circ\,t$

so that after the time found in part (f), the ball has traveled

$v_0\cos63^\circ(2.9\,\mathrm s)=11\,\mathrm m$

4 0

4 years ago