Answer:
The required equation is y(t) = -10.34 + 0.4t + 10.4e^(-0.038t)
The velocity is the first derivative of y(t)
The acceleration is the second derivative of y(t).
Explanation:
The required equation is found by taking the first and second derivative for velocity and acceleration respectively and setting the equations given to the boundary conditions given. The complete solution can be found in the attachment below.
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Answer:
Initial speed of the spaceship 1, v = 2 m/s
Explanation:
Given that :
Mass of spaceship 1 and 2 that have equal mass are 300 kg
Initial momentum of the spaceship 1 is 600 kg-m/s
To find :
We need to find the initial momentum of spaceship 1.
Solve :
The momentum of an object is equal to the product of mass and its velocity. Its SI unit is kg-m/s. Mathematically, it is given by :
v = 2 m/s
Therefore the initial speed of spaceship 1 is 2 m/s. Hence, this is the required solution.
Answer:
A. 10 N
B. 20 N
C. 1,000 N
Explanation:
D. According to Newton's Third Law, in the simplest terms, each and every action (force) has an equal but opposite reaction. So when the air pushes out to the left, the pressure of the air being released propels the balloon to the right. Therefore, Newton's Third Law is followed in this scenario. That is the same case for the above three questions as well.