Answer:
a = -5.10 m/s^2
her acceleration on the rough ice is -5.10 m/s^2
Explanation:
The distance travelled on the rough ice is equal to the width of the rough ice.
distance d = 5.0 m
Initial speed u = 9.2 m/s
Final speed v = 5.8 m/s
The time taken to move through the rough ice can be calculated using the equation of motion;
d = 0.5(u+v)t
time t = 2d/(u+v)
Substituting the given values;
t = 2(5)/(9.2+5.8)
t = 2/3 = 0.66667 second
The acceleration is the change in velocity per unit time;
acceleration a = ∆v/t
a = (v-u)/t
Substituting the values;
a = (5.8-9.2)/0.66667
a = -5.099974500127
a = -5.10 m/s^2
her acceleration on the rough ice is -5.10 m/s^2
Answer:
So coefficient of kinetic friction will be equal to 0.4081
Explanation:
We have given mass of the block m = 0.5 kg
The spring is compressed by length x = 0.2 m
Spring constant of the sprig k = 100 N/m
Blocks moves a horizontal distance of s = 1 m
Work done in stretching the spring is equal to 
This energy will be equal to kinetic energy of the block
And this kinetic energy must be equal to work done by the frictional force
So 
So coefficient of kinetic friction will be equal to 0.4081
Answer:
= 3521m/s
The tangential speed is approximately 3500 m/s.
Explanation:
F = m * v² ÷ r
Fg = (G * M * m) ÷ r²
(m v²) / r = (G * M * m) / r²
v² = (G * M) / r
v = √( G * M ÷ r)
G * M = 6.67 * 10⁻¹¹ * 5.97 * 10²⁴ = 3.98199 * 10¹⁴
r = 32000km = 32 * 10⁶ meters
G * M / r = 3.98199 * 10¹⁴ ÷ 32 * 10⁶
v = √1.24 * 10⁷
v = 3521.36m/s
The tangential speed is approximately 3500 m/s.
Answer:
<h2>7000 N</h2>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 1750 × 4
We have the final answer as
<h3>7000 N</h3>
Hope this helps you
Correct your answer to the amount of significant figures the questions wants
