The average rate at which the cable does work is 294,000 J/s.
The given parameters:
- <em>mass, m = 3000 kg</em>
- <em>height, h = 200 m</em>
- <em>time of motion, t = 20 s</em>
The average rate at which the cable does work is calculated as follows;
Thus, the average rate at which the cable does work is 294,000 J/s.
Learn more about energy and power here: brainly.com/question/13387946
Answer:
-2.79 m/s²
Explanation:
Given:
v₀ = 20 m/s
v = 11 m/s
Δx = 50 m
Find: a
v² = v₀² + 2aΔx
(11 m/s)² = (20 m/s)² + 2a (50 m)
a = -2.79 m/s²
Round as needed.
Answer:
because switch moves after a waiter
Explanation:
Explanation:
'What is the magnitude of the force needed to stop the horses and bring the box into equilibrium?' ≈42N; according to the vectors rules.
'Where would you locate the rope to apply the force?' - in point D.
PS. zoom out the attached picture.
-- The area under a velocity/time graph, between two points in time, is the difference in displacement during that period of time.
-- The area under a speed/time graph, between two points in time, is the distance covered during that period of time.
