Question

An airplane has a mass of 3.1x10^4 kg and takes off under the influence of a constant net force of 3.7x10^4 N. What is the net force that acts of the plane's 78-kg pilot?

Answer 1

Answer:

Net force that acts on the pilot = 93 N (rounded off to nearest 1 N)

Explanation:

An airplane has a mass of 3.1 × $10^{4}$ Kg

The applied force for it to take off = 3.7 × $10^{4}$ N

According to Newton's second law of motion; applied force (F) is directly proportional to the product of mass (M) and acceleration (A) of the object.

i.e F ∝ MA

This means that the applied force (F) is also directly proportional to the mass (M) of the object.

i.e F ∝ M

Acceleration (A) in this case is constant.

If the airplane's mass = 3.1 × $10^{4}$ kg requires 3.7 × $10^{4}$ N to take off,

Then the pilot's mass of 78 kg will require;

$\frac{78 * 3.7 * 10^4}{3.1 * 10^4}$ = 93.09677419 N = 93N (rounded off to nearest 1 N)