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nekit [7.7K]
3 years ago
5

The motion of a particle is given by the equation v = 8t3 – ½ t2 + 4t, where v is in meters and t is in seconds. Compute the val

ue of a at t=0. I got 98 m/s^2 but the answer key says 50m/s^2 so I think it must have been a typo. Can someone please check?
Physics
1 answer:
Jlenok [28]3 years ago
4 0

Answer:

4 m/s²

Explanation:

v(t) = 8t³ – ½ t² + 4t

Acceleration is the first derivative of velocity with respect to time.

a = dv/dt

a = 24t² – t + 4

At t = 0, the acceleration is:

a = 4

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The film thickness will need to be increased by λfilm/4 for it to be able to give a destructive interference.

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Convert to the fractional equivalent and reduce 21.12
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The decimal point is placed after two digits starting from the end. For each decimal place, we can write the number divided by 100.

21.12 can be written as \frac{2112}{100}.

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\frac{2112}{100}= \frac{156}{50}

The numerator and denominator can be divided by 2 again:

\frac{78}{25}

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You can increase the vapor pressure of a liquid by:
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4 0
3 years ago
Determine the critical crack length for a through crack contained within a thick plate of 7150-T651 aluminum alloy that is in un
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Explanation:

Formula to determine the critical crack is as follows.

          K_{IC} = \gamma \sigma_{f} \sqrt{\pi \times a}

  \gamma = 1,     K_{IC} = 24.1

  [/tex]\sigma_{y}[/tex] = 570

and,   \sigma_{f} = 570 \times \frac{3}{4}

                       = 427.5

Hence, we will calculate the critical crack length as follows.

      a = \frac{1}{\pi} \times (\frac{K_{IC}}{\sigma_{f}})^{2}

        = \frac{1}{3.14} \times (\frac{24.1}{427.5})^{2}

       = 10.13 \times 10^{-4}

Therefore, largest size is as follows.

            Largest size = 2a

                                 = 2 \times 10.13 \times 10^{-4}

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Thus, we can conclude that the critical crack length for a through crack contained within the given plate is 20.26 \times 10^{-4}.

4 0
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