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andre [41]
3 years ago
9

Write repeating decimal 0.027272727 ... as a fraction.

Mathematics
1 answer:
11111nata11111 [884]3 years ago
4 0

Answer:

27/100

Step-by-step explanation:

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Hi I really need help with a and b. thank you
Len [333]
A) To solve this equation, you would need to fill in the blank with a substitute. Let x represent the unknown number. 
\frac{27}{45} = \frac{x}{5}

Next, you would cross multiply. 
135 = 45x

Now, the last step would be to isolate the x. To do this, you would divide both sides by 45. 
3 = x

\frac{27}{45} = \frac{3}{5}

b) To solve this equation, you would need to fill in the blank with a substitute. Let x represent the unknown number. 
\frac{2}{6} = \frac{3}{x}
Next, you would cross multiply. 
18 = 2x

Now, the last step would be to isolate the x. To do this, you would divide both sides by 2. 
9 = x

\frac{2}{6} =\frac{3}{9}

I hope this helps!
6 0
3 years ago
PLZZZ HELP WITH GEOMETRY ;(
Tju [1.3M]

Answer:

lhh

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
One way to show that two triangles are similar is to show that
avanturin [10]

Answer:

show that the three sets of corresponding sides are in proportion. If the three sets of corresponding sides of two triangles are in proportion, the triangles are similar.

Step-by-step explanation:

7 0
3 years ago
Name an angle bisector shown in the figure.<br><br><br> DE<br><br> AB<br><br> GB<br><br> CF
expeople1 [14]

Answer:

CF

Step-by-step explanation:

we know that

An <u><em>angle bisector</em></u> is a line that divide an angle into two equal angles.

In this problem

m\angle ACF=m\angle FCD ---> given problem

m\angle ACD=m\angle ACF+m\angle FCD ---> by addition angle postulate

so

CF is an angle bisector of angle m\angle ACD

6 0
3 years ago
At Prairieview Middle School, 100 students participate in at least one of three after-school clubs: soccer club, art club, and g
Tresset [83]

Answer:

17

Step-by-step explanation:

Number of students in soccer club, n(S) = 50

Number of students in Art club, n(A) = 53

Number of students in Gaming club, n(G)

n(S \cup A\cup G) = 100

n(S \cap A\cap G) = 9

n(S \cap A) = 20

n(A \cap G) = 35

n(G \cap S) = 29

Formula:

n ( A ∪ B ∪ C ) =  n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )

Putting the values:

100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9

100 = 112 + n(G) - 84

n(G) = 72

Number of students in gaming club only = n(G) - n(G \cap S) - n(A \cap G) + n(S \cap A\cap G)

= 72 - 35 - 29 + 9

= <em>17</em>

6 0
3 years ago
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