Answer:
lets set the ratio -A/HA as R:
pH = pKa + log(R,10) => pKa + log10(R)
pH = 5.5
pKa = 4.76
R => 10^(pH - 4.76)
10^(pH - 4.76) => 5.4954
Given R (-A/HA) a number bigger than 1, then the concentration of -A is bigger than HA
Explanation:
Answer:
2621.75 j heat is required to increase the temperature 25.5°C to 46°C.
Explanation:
Given data:
Mass of sample = 142.1 g
Initial temperature = 25.5°C
Final temperature = 46°C
Specific heat capacity of Al = 0.90 J/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 46°C - 25.5°C
ΔT = 20.5°C
Q = 142.1 × 0.90 J/g.°C × 20.5°C
Q = 2621.75 j
Thus, 2621.75 j heat is required to increase the temperature 25.5°C to 46°C.
Answer:
Total we want 48 titanium to make 12.0moles
