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olga_2 [115]
3 years ago
5

Which of the following changes occurs in the nucleus when a position particle is given off

Chemistry
1 answer:
sineoko [7]3 years ago
8 0

Explanation:

When the position particle is given off, the nucleus' atom's turn to a cluster and the wavelength becomes shorter. Hope this helps!

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While a certain isotope decays, it emits photons. What kind of decay is happening?
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The correct answer is Gamma decay. It happens after beta and alpha decay because what's left after those two can enter a new process of gamma decay. This releases gamma rays which is a more complex term for the photons that you mentioned before. These rays can be dangerous for humans so care not to get caught in them.
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an engineering team is conducting a trial launch of a few rocket . which part is the engineering process is the team in ?
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Evaluate the result (Apex)

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A certain ore is 37.3% nickel by mass how many kilograms of this ore would you need to dig up to have 10.0g of nickel
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3 years ago
The enthalpy of fusion of solid n-butane is 4.66 kJ/mol. Calculate the energy required to melt 58.3 g of solid n-butane.
adelina 88 [10]

Answer : The energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

Explanation :

First we have to calculate the moles of n-butane.

\text{Moles of n-butane}=\frac{\text{Mass of n-butane}}{\text{Molar mass of n-butane}}

Given:

Molar mass of n-butane = 58.12 g/mole

Mass of n-butane = 58.3 g

Now put all the given values in the above expression, we get:

\text{Moles of n-butane}=\frac{58.3g}{58.12g/mol}=1.00mol

Now we have to calculate the energy required.

Q=\frac{\Delta H}{n}

where,

Q = energy required

\Delta H = enthalpy of fusion of solid n-butane = 4.66 kJ/mol

n = moles = 1.00 mol

Now put all the given values in the above expression, we get:

Q=\frac{4.66kJ/mol}{1.00mol}=4.66kJ

Thus, the energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

7 0
3 years ago
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