How many grams are 2.50 * 10^23 molecules of CaO?
1 answer:
134.56 grams are 2.50 * 10^23 molecules of CaO.
Explanation:
According to Avagadro hypothesis, 1 mole of a substance contain 6.023 x 10^23 molecules or particles.
Data given:
Number of molecules of CaO =
FORMULA USED IN CALCULATION:
number of molecules = 6.02 x 10^23 x number of moles of CaO
At first number of moles is calculated:
= 2.4 moles of CaO is present
to calculate the mass of CaO in grams formula used is
mass = atomic mass x number of moles
atomic mass of CaO = 56.07 grams/mole
mass = 2.4 x 56.07
= 134.56 grams of calcium oxide is present is 2.50 * 10^23 molecules of CaO.
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<u>Answer:</u> The mass of arsenic found in the sample is 0.25 mg
<u>Explanation:</u>
ppm is the amount of solute (in milligrams) present in kilogram of a solvent. It is also known as parts-per million.
To calculate the ppm of oxygen in sea water, we use the equation:
Both the masses are in grams.
We are given:
Concentration of arsenic = 5 ppm
Mass of sample = 50 g
Putting values in above equation, we get:
<u>Conversion factor used:</u> 1 g = 1000 mg
Hence, the mass of arsenic found in the sample is 0.25 mg