134.56 grams are 2.50 * 10^23 molecules of CaO.
Explanation:
According to Avagadro hypothesis, 1 mole of a substance contain 6.023 x 10^23 molecules or particles.
Data given:
Number of molecules of CaO =
FORMULA USED IN CALCULATION:
number of molecules = 6.02 x 10^23 x number of moles of CaO
At first number of moles is calculated:
= 2.4 moles of CaO is present
to calculate the mass of CaO in grams formula used is
mass = atomic mass x number of moles
atomic mass of CaO = 56.07 grams/mole
mass = 2.4 x 56.07
= 134.56 grams of calcium oxide is present is 2.50 * 10^23 molecules of CaO.
Given :
2NOBr(g) - -> 2NO(g) + Br2(g)
Initial pressure of NOBr , 1 atm .
At equilibrium, the partial pressure of NOBr is 0.82 atm.
To Find :
The equilibrium constant for the reaction .
Solution :
2NOBr(g) - -> 2NO(g) + Br2(g)
t=0 s 1 atm 0 0
1( 1-2x) 2x x
So ,
At equilibrium :
Hence , this is the required solution .