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3 years ago

Find the volume of the following cylinder using its net.

Mathematics

1 answer:

artcher [175]3 years ago

6 0

Check the picture below.

$\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} \pi r^2=&area~of\\ &circular\\ &base\\ h=&height\\ \cline{1-2} \pi r^2=&28.26\\ h=&8 \end{cases}\implies V=(28.26)(8)\implies V=226.08$

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If candy canes cost $0.89 per dozen, how much would it cost to buy candy canes

Illusion [34]

Answer:

$356

Step-by-step explanation:

So if they are 400 students we need to:

0.89*400=$356

4 0

3 years ago

Read 2 more answers

Solve for x. 2=4x-6

77julia77 [94]

Answer:

x = 2

Step-by-step explanation:

Rewrite the equation as 4x - 6 = 2

Move all terms not containing x to the right side of the equation:

Add 6 to both sides of the equation.

4x = 2 + 6

Add 2 and 6.

4x = 8

Divide each term by 4 and simplify.

Divide each term in 4x = 8 by 4.

$\frac{4x}{4} =\frac{8}{4}$

Reduce the expression by cancelling the common factors.

$x=\frac{8}{4}$

Divide 8 by 4.

x = 2

8 0

3 years ago

The random variable X is exponentially distributed, where X represents the waiting time to be seated at a restaurant during the

erastova [34]

Answer:

The probability that the wait time is greater than 14 minutes is 0.4786.

Step-by-step explanation:

The random variable X is defined as the waiting time to be seated at a restaurant during the evening.

The average waiting time is, β = 19 minutes.

The random variable X follows an Exponential distribution with parameter $\lambda=\frac{1}{\beta}=\frac{1}{19}$ .

The probability distribution function of X is:

$f(x)=\lambda e^{-\lambda x};\ x=0,1,2,3...$

Compute the value of the event (X > 14) as follows:

$P(X>14)=\int\limits^{\infty}_{14} {\lambda e^{-\lambda x}} \, dx=\lambda \int\limits^{\infty}_{14} {e^{-\lambda x}} \, dx\\=\lambda |\frac{e^{-\lambda x}}{-\lambda}|^{\infty}_{14}=e^{-\frac{1}{19} \times14}-0\\=0.4786$