Chickens have 1 head and 2 legs
rabbits had 1 head and 4 legs
total heads is 30
c+r=30
total legs is 98
2c+4r=98
divide by 2
c+2r=49
multiply top equation by -1 and add to 2nd equation
-c-r=-30
<u>c+2r=49 +</u>
0c+1r=19
r=19
sub back
c+r=30
c+19=30
minus 19
c=11
11 chickens
19 rabbits
4w-12=6w-36+14
4w-12=6w-22
10=2w
5=w
(I think)
Answer:
Step-by-step explanation:
[3, 1] and [0, −3]
I am joyous to assist you anytime.
<h3>
Answer:</h3>
- A) p = 5, one solution
- B) no solutions
- C) infinite solutions
<h3>
Step-by-step explanation:</h3>
A) Add 19-5p to each side of the equation:
... 10 = 2p
... 5 = p . . . . . divide by the coefficient of p
B) Subtract 5p from both sides of the equation:
... -9 = -19 . . . . . there is <em>no value of p</em> that will make this true. (No solution.)
C) Subtract 5p from both sides of the equation:
... -9 = -9 . . . . . this is true for <em>every value of p</em>. (Infinite solutions.)
We can find the side length of square 3 by dividing by 4, which is 9.
Then, we find the side length of square 2 by dividing it by 4, which is 12.
To find the AREA of square 1, we do a^2+b^2=c^2. This is basically adding up area of square 1 and square 2 to get square 3.
a^2+b^2=c^2
9^2+12^2=c^2
81+144=225
So the area is 225 units.
