Ba(OH)2 is an basic solution. It has more OH- ions than H+ ions. pOH should be calculated to find out its pH
The reaction is
Ba(OH)2 ⇒ Ba2+ (aq) + 2 OH-(aq)
One mole barium hydroxide releases 2 moles hydroxide ions.
Use that ratio to calculate molarity (M) of OH- ions [OH-]. The ratio is 1:2.
0.10 M Ba(OH)2 release 2*0.10 M= 0.02 M OH- ions
[OH-]= 0.02
pOH= - log [OH-] = - log 0.02 = 1.7
Thats not the answer! We found pOH of the solution before titration.
pH and pOH relationship is shown by formula of pH+pOH= 14
pH= 14-pOH
pH= 14-1.7= 12.3
1) Chemical equation of the equilibrium
BaCrO4⇄ Ba (2+) + CrO4 (2-)
2) Ksp equation
Ksp = [Ba(2+)] [CrO4 (2-)]
where Ksp = 1.0 * 10^ - 10 and [Ba(2+)] = [CrO4(2-)] = x
3) Calculations
1.0 * 10^ -10 = x * x
=> x^2 = 1.10 * 10^-10
=> x = √[1.0 * 10^ -10] = 0.000010
Answer: [Ba(2+)] = [CrO4(2-)] = 0.00001 M
Answer:
If I have an unknown quantity of gas at a pressure of 1.2 atm, a volume of 31 liters, ... If I contain 3.0 moles of gas in a container with a volume of 60. liters and at a ... Mixtures of helium and oxygen are used in scuba diving tanks to help prevent ... volume of 5.00 Lat 25.0C. Calculate the partial pressure of each gas and the ...
Explanation:
Answer:
A
Explanation:
A catalyst refers to an enzyme composed of peptides in their tertiary conformation.
The addition of a catalyst provides a new path to the reaction and the reaction proceeds in a faster way compared to the reaction without a catalyst.
The peptides are arranged in such a way that they form a pore-like structure which allows the binding of the substrate molecules by forming a temporary covalent bond. These bonds lower the activation energy of the complete reaction which is required to initiate a reaction.
In the given diagram, the activation reaction is represented by the letter "A" and therefore a catalyst will lower and alter the value of A.
Thus, Option-A is correct.
