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3 years ago

PLZ HELP I WILL MARK BRAINIEST

Physics

1 answer:

Yuri [45]3 years ago

7 0

Gravitational potential energy is the energy stored in an object due to its height above the Earth.

Explanation:

Gravitational potential energy is an energy that an object has as a result of its position in a gravitational field.

For an object which is near to Earth surface is gravitational acceleration is considered to be constant at 9.8 m/s².

Gravitational potential energy is also defined as the amount of work done to move an object having certain mass from one point to another point against gravitational force. It is calculated as mass multiplied by height to which an object is moved.

Some examples are water stored in a dam, ball kept on the top of a ramp, book kept of a shelf, etc.

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Blackbody radition is white give reasons.?

Nimfa-mama [501]

Answer:An object that absorbs ALL radiation falling on it, at all wavelengths, is called a blackbody. When a blackbody is at a uniform temperature, its emission has a characteristic frequency distribution that depends on the temperature. ... As its temperature increases further it becomes yellow, white, and ultimately blue-white

Explanation:

7 0

3 years ago

A 2 kg ball with an initial velocity of 10 m/s moves at an angle 60º above the +x-direction. The ball hits a vertical wall and b

kow [346]

Answer:

I = 20 i ^ N s

Explanation:

For this problem let's use the Impulse equation

I = Δp = m $v_{f}$ - v₀

The impulse and the velocity are vector quantities, let's calculate on each axis, let's decompose the velocity

cos 60 = vₓ / v

vₓ = v cos 60

sin60 = $v_{y}$ / v

$v_{y}$ = v sin60

vₓ = 10 cos 60

$v_{y}$ = 10 sin60

vₓ = 5.0 m / s

$v_{y}$ = 8.66 m / s

Let's calculate the impulse on each axis

X axis

Iₓ = m $v_{xf}$ - m vₓ₀

How the ball bounces

$v_{xf}$ = - vₓ₀ = vₓ

Iₓ = 2 m vₓ

Iₓ = 2 2 5

Iₓ = 20 N s

Y axis

$I_{y}$ = m $v_{yf}$ - m vyo

On the axis and the ball does not change direction so

$v_{yf}$ = vyo

$I_{y}$ = 0

The total momentum is

I = Iₓ i ^ + $I_{y}$ j ^

I = 20 i ^ N s

7 0

3 years ago

!!!

slavikrds [6]

Answer:

0.5

Explanation:

I think it is this beacause if u have the answer you have that

5 0

2 years ago

A merry-go-round accelerating uniformly from rest achieves itsoperating speed of 2.5rpm in five revolution.

g100num [7]

Answer:

(A) The magnitude of its angular acceleration 1.09 x 10⁻³ rad/s²

(B) Time of motion 240.2 s

Explanation:

Given;

final angular speed, ωf = 2.5 RPM

angular distance, θ = 5 rev = 5 x 2π = 10π rad

initial angular speed, ωi = 0

final angular speed in rad/s;

$\omega_f = \frac{2.5 \ rev}{min} \times \ \frac{2\pi}{1 \ rev} \times \ \frac{1 \min}{60 s} = 0.2618 \ rad/s \\$

(A) the magnitude of its angular acceleration(rad/s^2);

$\omega_f^2 = \omega_i^2 + 2\alpha \theta\\\\(0.2618)^2 = 0 + (2\times 10\pi)\alpha\\\\0.0685 = 20\pi \alpha\\\\\alpha = \frac{0.0685}{20\pi} \\\\\alpha = 1.09\times 10^{-3} \ rad/s^2$

(B) Time of motion;

$\omega_f = \omega_i + \alpha t\\\\0.2618 = 0 + 1.09\times 10^{-3} t\\\\t = \frac{0.2618}{1.09\times 10^{-3}} \\\\t = 240.2 \ s$

7 0

3 years ago

In the roman soldier model for refraction, a muddy stream crosses the road they are on walking on at 45. Will the soldiers in th

Mamont248 [21]

There are different refractive errors that are common and some of them are:

Nearsightedness (myopia) makes far-away objects look blurry.
Farsightedness (hyperopia) makes nearby objects look blurry.
Astigmatism can make far-away and nearby objects look blurry or distorted.
Presbyopia makes it hard for middle-aged and older adults to see things up close

<h3>What is Refraction?</h3>

This refers to the study of light phenomena that deflects when it passes through a medium in an oblique manner to another medium of a varying density.

Hence, we can see that there are everyday examples of refraction in simple terms which occurs and some of them are:

Glass
Human eyes
Ice crystals
Pickle jar
Microscope, etc.

Hence, we can see that your question is incomplete, so I gave you a general overview to help you get a better understanding of the concept of refraction.