Answer:
The radius of the circle is 
Step-by-step explanation:
we know that
The circumference of a circle is equal to
In this problem we have
substitute and solve for r
Answer:
L.C.M of 432 and 486: 3888
H.C.F of 432 and 486: 54
Step-by-step explanation:
Answer:
Step-by-step explanation:
The x and y intercepts occur when either x or y = 0
For the y intercept, x = 0
3(0) - 5y + 15 = 0
- 5y + 15 = 0 Subtract 15 from both sides.
-5y = - 15 Divide by - 5
-5y / -5 = - 15/-5
y = 3
For x intercept, y = 0
3x - 5(0) + 15 = 0
3x + 15 = 0 Subtract 15 from both sides
3x = - 15 Divide by 3
3x/3 = - 15/3
x = - 5
xintercept = (-5,0)
yintercept = (0,3)
Answer: D (5/2, -17/4)
Step-by-step explanation: Using elimination your goal is to get rid or 1 variable so you can solve for the one that's left. By adding the -2y and 2y you will get 0. You will also add the 3x+x (4x) and -1+11 (10). You have now gotten rid of the y and have 4x=10. By dividing each side by 4 we now know x =2.5. D is the only possible solution with x=2.5 (5/2) but to solve for y you plug 2.5 in to an equation as x so) x-2y=11
2.5-2y=11
-2y=8.5 Answer D (5/2,-17/4) y=-17/4 (4.25)
Answer:
Solutions are 2, -1 + 0.5 sqrt10 i and -1 - 0.5 sqrt10 i
or 2, -1 + 1.58 i and -1 - 1.58i
(where the last 2 are equal to nearest hundredth).
Step-by-step explanation:
The real solution is x = 2:-
x^3 - 8 = 0
x^3 = 8
x = cube root of 8 = 2
Note that a cubic equation must have a total of 3 roots ( real and complex in this case). We can find the 2 complex roots by using the following identity:-
a^3 - b^3 = (a - b)(a^2 + ab + b^2).
Here a = x and b = 2 so we have
(x - 2)(x^2 + 2x + 4) = 0
To find the complex roots we solve x^2 + 2x + 4 = 0:-
Using the quadratic formula x = [-2 +/- sqrt(2^2 - 4*1*4)] / 2
= -1 +/- (sqrt( -10)) / 2
= -1 + 0.5 sqrt10 i and -1 - 0.5 sqrt10 i
