Answer:
Same magnitude of the 10 nc charge cause the electric field is external.
Explanation:
To do a better explanation, let's go and suppose we have an electric field of, 1300 N/C with a 10 nC charge.
As the system we are talking about is really big, and the charge is small, we can assume always if the charge is sitting right in the same point where the electric field is, then, the electric field would not suffer any kind of alteration in it's value. Therefore, no matter what value of the charge is sitting here, the electric field is independent of the charge, so it would not feel any alteration. However, the force that the charge is feeling would be stronger than in the first case.
F = qE
If charge is doubled, then the force would be bigger in the second case than in the first case, but electric field remain the same value.
Answer:
0.6 μC
Explanation:
C = capacitance of the capacitor = 100 x 10⁻¹² F
d = separation between the plates of capacitor = 1 mm = 1 x 10⁻³ m
E = Electric field = 6 x 10⁶ N/C
Q = Amount of charge
V = Potential difference
Potential difference is given as
V = E d
Amount of charge stored is given as
Q = CV
hence
Q = C E d
inserting the values
Q = (100 x 10⁻¹²) (6 x 10⁶) (1 x 10⁻³)
Q = 6 x 10⁻⁷ C
Q = 0.6 μC
Answer:
<h2>50 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 100 × 0.5
We have the final answer as
<h3>50 J</h3>
Hope this helps you
-- You've GOT the kinetic energy of the bullet.
-- That's the amount of work that has to be done to stop it.
-- work = (avg force) x (penetration) and they just gave you the average force.
-- Did you think it would be this easy ?
