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Hatshy [7]
3 years ago
5

Every day, Jason's burrito stand uses 2 bags of tortillas. For how many days will 3/4 of tortillas last?

Mathematics
1 answer:
Katarina [22]3 years ago
4 0
3/8 of 1 day is your answer
You might be interested in
A chain weighs 10 pounds per foot. How many ounces will 3 inches weigh?
KengaRu [80]

Answer:

40 ounces

Step-by-step explanation:

One foot = 12 inches

3 inches is 1/4 of a foot

Divide 10 pounds by 4 to get 2.5 pounds

Convert to ounces

3 0
3 years ago
a cylinder has a volume of 108 cubic inches. the base has a radius of 3 inches and a height of 8 inches. what is the height of t
nikdorinn [45]
The answer is four because three times eight times three is 108

8 0
3 years ago
A substantial portion of inventory owned by Prentiss Sporting Goods was recently destroyed when the roof collapsed during a rain
kkurt [141]

Answer:

a) $150,225

b) $450,675

c) $152,425

d) $17,700

Step-by-step explanation:

Given:

Beginning inventory = $204,300

Purchases to date of storm = $398,800

Sales to date of storm = $600,900

The value of undamaged inventory counted = $134,725

Prentiss’s gross margin percentage = 25% of sales

a) Now,

Gross margin = Sales × Gross margin percentage

= $600,900 × 25%

= $150,225

GROSS MARGIN ( DOLLARS)= 113506

b) Cost of goods sold = Sales - Gross margin

= $600,900 - $150,225

= $450,675

c) Ending inventory

= Beginning inventory + purchase - Cost of goods sold

= $204,300  + $398,800  - $450,675

= $152,425

d) Amount of lost inventory

= Ending inventory - Undamaged inventory

= $152,425 - $134,725

= $17,700

5 0
3 years ago
1. 2300 hrs = pm
meriva
1. 2300-12:00=11:00pm
2. x+48+29=180° in a triangle
x=103°
3. 9 is in the one-hundredth place
4. 159,000
5. 298×21=6258 but to estimate you can get close with 300×21=6,300
6. 5.3×7=$37.10
7. 258,008-10,000=248,008
8. 1/4+1/2+7/8
LCD is 8 so 2/8+4/8+7/8 so (2+4+7)/8=13/8
8 0
3 years ago
What logically could have gone wrong?
Illusion [34]
The steps to construct a circle circumscribing a triangle are:

- Construct a perpendicular bisector of one side of the triangle
- Construct another perpendicular bisector of another side of the triangle
- The point of intersection of these two perpendicular bisectors is the center
  of the circle, we are about to construct.
- Adjust the width of the compass between the intersection point to any of
  the corners of the triangle. This width should be the same for all three
  vertices
- With the pointer of the compass is located at the intersection point, construct the circle

What could possibly go wrong when the  circle only passes two vertices, is the width of the compasses has changed while constructing the circle

Answer: First option

7 0
3 years ago
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