Answer:
NaNO₃ and AgCl are the two products that can be formed.
Sodium nitrate, an aqueous solution and a solid silver chloride (precipitate)
Explanation:
We determine the dissociation of both salts
AgNO₃ (aq) → Ag⁺ (aq) + NO₃⁻ (aq)
NaCl (aq) → Na⁺ (aq) + Cl⁻ (aq)
We make the ionic equation:
Ag⁺ (aq) + NO₃⁻ (aq) + Na⁺ (aq) + Cl⁻ (aq) → NaNO₃(aq) + AgCl (s) ↓
8.Carbonate tetranitride
9.Zinc chloride
10.Sodium cyanide
11.Magnesium Phosphate
B im just typing more because it has to be longer than 20 characters
Answer: The millimoles of sodium carbonate the chemist has added to the flask are 256
Explanation:
Molarity is defined as the number of moles dissolved per liter of the solution.
To calculate the number of moles for given molarity, we use the equation:
.....(1)
Molarity of
solution = 1.42 M
Volume of solution = 180.0 mL
Putting values in equation 1, we get:

Thus the millimoles of sodium carbonate the chemist has added to the flask are 256.
Answer:
271.0 L
Explanation:
Given data:
Number of moles of hydrogen = 12.1 mol
Volume = ?
Solution:
The one mole of gas at standard temperature and pressure occupy the volume of 22.4 L.
One mole volume = 22.4 L
For 12.1 mol,
12.1 mol × 22.4 L / 1 mol
271.0 L
Now by putting the standard conditions we can calculate the number of moles and check the answer weather it is wrong or right.
Formula:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
standard temperature = 273.15 K
standard pressure = 1 atm
Now we will put the values in formula.
PV = nRT
n = 1 atm × 271.0 L / 0.0821 atm.L/mol.K × 273.15 K
n = 271.0 L .atm / 22.4 atm. L/mol
n = 12.1 mol
so answer is correct