Answer:
3rd option
Step-by-step explanation:
Since the centre of dilatation is at the origin then multiply the coordinates by 
K (- 3, 9 ) → K' (- 3(
), 9(
) ) → K' (- 1, 3 )
L (- 9, 0 ) → L' (- 9(
), 0 (
) ) → L' (- 3, 0 )
M (2, - 8 ) → M' (2 (
), - 8 (
) ) → M' (
, -
)
N (6, 4 ) → N' (6 (
) , 4 (
) ) → N' ( 2,
)
Answer: 0.9762
Step-by-step explanation:
Let A be the event that days are cloudy and B be the event that days are rainy for January month .
Given : The probability that the days are cloudy = 
The probability that the days are cloudy and rainy = 
Now, the conditional probability that a randomly selected day in January will be rainy if it is cloudy is given by :-

Hence, the probability that a randomly selected day in January will be rainy if it is cloudy = 0.9762
Answer:
The answer to your question is:
a) f(a) -2 = a² - 3
b) f(a - 2) = a² - 4a + 3
c) f(b + d) = b² + 2bd + d² - 1
Step-by-step explanation:
a. f(a) - 2 = (a)² - 1 - 2
f(a) -2 = a² - 3
b. f(a - 2) = (a - 2)² - 1
f(a - 2) = a² - 4a + 4 - 1
f(a - 2) = a² - 4a + 3
c. f(b + d) = (b + d)² - 1
f(b + d) = b² + 2bd + d² - 1