Time period = 1 / frequency
Time period = 1 / 250 th of a second
Frequency and speed = wavelength.
××

×
50N is your force and the acceleration is -9.8m/s^2 due to gravity.
So, you just plug that in.

BUT you know that mass cannot be negative, so you just disregard the negative sign and the mass of the rock is 5.102 grams.
Answer:
i) 3.514 s, ii) 5.692 m/s
Explanation:
i) We can use Newton's second law of motion to find out how long does it take for the Eagle to touch down.
as the equation says for free-falling
h = ut +0.5gt^2
Here, h = 10 m, g = acceleration due to gravity = 1.62 m/s^2( on moon surface)
initial velocity u = 0
10 = 0.5×1.62t^2
t = 3.514 seconds
Therefore, it takes t = 3.514 seconds for the Eagle to touch down.
ii) use Newton's 1st equation of motion to calculate the velocity of the lunar module when it hits the surface of the moon
v = u + gt
v = 0+ 1.62×3.514
v= 5.692 m/s
Answer:
The bulb B glows brighter.
Explanation:
Given that,
A glows brightly and B glows dimly.
According to ohm's law,
Two light bulbs A and B are connected in series to a battery then the current will be same in both bulbs and the resistance is high of bulb A and low in bulb B.
If bulb A connect to a battery and bulb B connect to a same battery separately.
Then bulb B glows brighter because the resistance is high in bulb A so the current will be low.
The resistance is low in bulb B so the current will be high.
Hence, The bulb B glows brighter.