It involves electrons.
The cathode is the electrode where electron deficient ions move to.
While the anode is electrode where electron excess ions move to.
So the relationship between Cathode and Anode involves electrons.
C.
Answer:
∈=
Explanation:
Using the Gauss Law to determine the electric field of the net flux at the surface of the nucleus
∈
The P is the charge density and 'Eo' is the constant of permittivity in free space
to find P





So replacing
∈
∈=
Answer:
The net Electric field at the mid point is 289.19 N/C
Given:
Q = + 71 nC = 
Q' = + 42 nC = 
Separation distance, d = 1.9 m
Solution:
To find the magnitude of electric field at the mid point,
Electric field at the mid-point due to charge Q is given by:



Now,
Electric field at the mid-point due to charge Q' is given by:



Now,
The net Electric field is given by:


The maximum speed of Tim is 16.95 m/s.
The given parameters:
- Mass of the rope, m = 71 kg
- Tension on the rope, T = 220 N
- Coefficient of kinetic friction, = 0.1
- Time of motion, t = 8 s
<h3>What is Newton's second law of motion?</h3>
- Newton's second law of motion states that, the force applied to an object is directly proportional to the product of mass and acceleration of the object.
The net force on Tim is calculated by applying Newton's second law of motion as follows;

Thus, the maximum speed of Tim is 16.95 m/s.
Learn more about net horizontal force here: brainly.com/question/21684583
Explanation:
Given that,
Frequency in the string, f = 110 Hz
Tension, T = 602 N
Tension, T' = 564 N
We know that frequency in a string is given by :
, T is the tension in the string
i.e.
, f' is the another frequency


f' =106.47 Hz
We need to find the beat frequency when the hammer strikes the two strings simultaneously. The difference in frequency is called its beat frequency as :



So, the beat frequency when the hammer strikes the two strings simultaneously is 3.53 beats per second.