Answer:
13
Step-by-step explanation:
a parallelogram has sides that are parallel to the opposite side. This means that y + 7 is going to be parallel to 20.
Two opposing sides of a parallelogram are parallel and equal
You know that the length of both of the sides is equivalent because the other set of opposing lines is also parallel (you can think of it as cutting off the line segment of y+7 and 20 at the same length. )
this means that we can set up the equation to find y as:
y + 7 = 20
then, you can proceed to find y by isolating it:
y + 7 = 20 ; so therefore
y + 7 = 20
- 7 -7
y = 13
y = 13
So, the value of y is 13
Answer:
A
Step-by-step explanation:
The additive inverse property states that if we have a number a, then:

Here, we have the equation:

And we divide both sides by 2:

To acquire:

So, we did <em>not</em> use the additive inverse property since we didn't add anything.
Instead, we used the<em> division property of equality</em> by dividing both sides by 2.
So, our answer is A.
And we're done!
C and d
when x = 2 , f(x) = x^2 = 4
and
when x = 1 f(x) = 5
The other commentor is right. The correct answer is 2-i
The second follow-up question is the second option
f(x) = (x<span> – (2 + </span>i))(x<span> – (2 –</span><span> i</span>))(x<span> – 5)
</span>The third follow-up question has these three answers.
9x^2
25x
25
Answer:
The number of footballs, basketballs and volleyballs were sold are 75, 36 and 15 respectively.
Step-by-step explanation:
Consider the provided information.
A football costs $35, a basketball costs $25 and a volleyball costs $15.
Let F represents the football, B represents the basketball and V represents the volleyball.
On a given day, the store sold 5 times as many footballs as volleyballs.
......(1)
They brought in a total of $3750 that day,
......(2)
The money made from basketballs alone was 4 times the money.
......(3)
By equation 1, 2 and 3.



Substitute the value of V in equation 1 and 3.


Hence, the number of footballs, basketballs and volleyballs were sold are 75, 36 and 15 respectively.