All categories

3 years ago

If Jamie is x years old and Jamie's brother pete is 3 years older show can I write an expression to represent their ages

1 answer:

6 0

X + 3 would be the expression representing pete's age.

if jamie's brother pete is 3 years older than jamie, and jamie's age is x, then jamie's age plus 3 years would be pete's age. for example, if jamie is 5:

5 + 3 = 8, making pete's age 8.

You might be interested in

Express 2x^2+8x+3 in the form 2(x+p)^2+q

e-lub [12.9K]

Answer:

2(x + 2)² - 5

Step-by-step explanation:

Given

2x² + 8x + 3

To obtain the required form use the method of completing the square.

The coefficient of the x² term must be 1, thus factor 2 out of 2x² + 8x

= 2(x² + 4x) + 3

add/subtract ( half the coefficient of the x- term)² to x² + 4x

= 2(x² + 2(2)x + 4 - 4) + 3

= 2(x + 2)² - 8 + 3

= 2(x + 2)² - 5

with p = 2 and q = - 5

4 0

4 years ago

Solve the system using substitution and describe your steps. <br> x=y-3 <br> 2x+y=12

Veseljchak [2.6K]

First you plug in for x,

2(y-3)+y=12

Then you solve for y
2y-5+y=12
-10y+y=12
-9y=12
-9y/9=12/-9
y=-1.333333333333333333333333333333333333333333333333333333333

5 0

3 years ago

PLEEASSEEEE Answer ASAP. Due in 5 Minutes. 25 points!!!!!!!!!

jonny [76]

Answer:

Here we will use the relationships:

$a^n*a^m = a^{n + m}$

$(a^n)^m = a^{n*m}$

$\frac{a^n}{a^m} = a^{n - m}$

And a number:

$a^n$

is between 0 and 1 if a is positive and larger than 1, and n is negative.

if a is positive and 0 < a < 1, then we need to have n positive such that:

0 < a^n < 1

A) $5^3*5^{-4} = 5^{3 + (-4)} = 5^{-1}$

This is between zero and 1,

B) $\frac{3^5}{3^{-6}} = 3^{5 - (-6)} = 3^{11}$

This is greater than 1, because the exponent is positive.

C) $(\frac{1}{4})^3*( \frac{1}{4})^2 = (\frac{1}{4})^{2 + 3} = (\frac{1}{4})^5$

Because a is smaller than 1, and the exponent is positive, then the expression is between 0 and 1.

D) $\frac{(-7)^5}{(-7)^7} = (-7)^{5 - 7} = -7^{-2}$

The exponent is negative (and pair) then the expression is between 0 and 1.

Remember that when the exponent is pair, we always have that:

(-N)^m = (N)^m

So (-7)^-2 = 7^-2

4 0

3 years ago

Three cube shaped boxes are stacked one above the other the volumes of two of the boxes are 1331 m³ each and the volume of the t

Pepsi [2]

So to find out the answer, you need to find out the dimensions of each cube. So for the 1331, it's 11 x 11 x 11. So you know that would be 11 meters high. Now the next cube. Then there's another 1331, so that would be another 11 meters high. Then 729, also 9 x 9 x 9, so that's going to be 9 meters high. Then add all the cube square roots. 11 + 11 + 9 = 31. So the height of the stacked boxes will be 31 meters.

5 0

3 years ago

What is the set of all solutions to the equation \sqrt{x + 2}= {-x} x+2 =−xsquare root of, x, plus, 2, end square root, equals

NARA [144]

Answer:

$x = 2$ or $x = -1$