starting from rest , a formula one car accelerates uniformly at 25m\s2 for 30secs. what distance does it cover in the last one s
1 answer:
The distance covered in the last second of motion is 737.5 m
Explanation:
The motion of the car is a uniformly accelerated motion, so we can use the suvat equations.
First of all, we have to find the velocity of the car when the last second of motion starts, that is the velocity of the car after t = 29 s. We can use the equation:
v = u + at
where
u = 0 is the initial velocity
is the acceleration
Substituting t = 29 s,
Now we can find the distance covered in the last second of motion by using
where
u = 725 m/s is the velocity at the beginning of the last second
t = 1 s is the time interval considered
is the acceleration
Substituting,
Note that the acceleration of is not realistic for a car, but I still have used the data of the problem.
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Answer:
The frequency of a wave is 35 Hz.
Explanation:
Speed of a wave is 140 m/s
Wavelength of a wave is 4 m
It is required to find the frequency. The relation between frequency, speed and the wavelength of a wave is given by :
f is frequency
So, the frequency of a wave is 35 Hz.
a) For 0 compressions:
potential energy = U = 0 J
kinetic energy = k = 0.383 J
total mechanical energy = E = 0.383 J
b) For compression of 1 cm:
potential energy = U = 0.0228 J
kinetic energy = k = 0.155 J
total mechanical energy = E = 0.383 J
c) For compression of 2 cm :
potential energy = U = 0.1104 J
kinetic energy = k = 0.272 J
total mechanical energy = E = 0.383 J
d) For compression of 3cm:
potential energy = U = 0.248 J
kinetic energy = k = 0.177 J
total mechanical energy = E = 0.383 J
<h3>Method for solving:</h3>The equations for kinetic energy is:
k= 1/2*m*
The equation for elastic potential energy is:
U= 1/2*ks*
Where,
m= mass of the block
v= velocity
ks= spring constant
x= displacement of the spring
(a)when compression= 0 cm
U= 1/2*ks*
U= 1/2*552*
= 0 J
Kinetic energy:
k= 1/2*m*
k= 1/2*(1.05)*
k= 0.383 J
Mechanical energy:
E= k + U
E= 0.383+0
E= 0.383 J
There will be no work done by friction or any other dissipative force, hence this energy will be conserved, or it will remain constant (like air resistance). This indicates that only spring potential energy will be created from the kinetic energy (there is no thermal energy due to friction, for example).
(b) spring potential = ?
U= 1/2* 457 N/m*
U= 0.0228 J
Since the mechanical energy must remain constant, we may calculate the kinetic energy using the mechanical energy equation:
E= k + U
0.383= k + 0.0228
k= 0.383 - 0.228
k= 0.155
(c)spring constant when x= 0.02
U= 1/2*552*
U= 0.1104 J
Using the equation of mechanical energy:
E= k +U
0.383= k+ 0.1104
k= 0.383 - 0.1104
k= 0.272 J
(d) U= 1/2*552*
U= 0.2484 J
E= 0.383 J
k = E - U
k= 0.383- 0.206
k= 0.177
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