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3 years ago

CALCULATING HALF LIFE

Physics

1 answer:

olga2289 [7]3 years ago

7 0

Answer:

N = 500Bq

Explanation:

No = 2000Bq

Time (T) = 10years

T½ = 5 years.

N = ?

T½ = In2 / λ

T½ = 0.693 / λ

λ = 0.693 / t½

λ = 0.693 / 5

λ = 0.1386

The ratio between the two activities is

(N / No) = e⁻^λt

N = No * e⁻^λt

N = 2000 * e^⁻⁰.¹³⁸⁶ * ¹⁰

N = 2000 * e⁻¹.³⁸⁶

N = 2000 * 0.25

N = 500Bq

The activity of Co-60 after 10 years would be 500Bq

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