Weight = Mass * gravity
= 1470* 9.8 = 14406 N ≈ 14,400 N
The new force would be 1.6 N.
Since the charges multiply as variables (q1)x(q2), then it would simply be double (q1)x(q2), or 1.6.
The Ohm's law is I(the strength of the current flowing in a conductor)= V(the potential difference applied to the ends) divided by R(resistance)
Answer:
part A ⇒ u = 1.28 m
part B ⇒v = 0.43 m
Explanation:
for u is the distance to the object from the mirror and v is the distance from the mirror to the image.
Part A:
the mirror equation is given by:
1/f = 1/v + 1/u
but we told that, v = 1/3u:
1/f = 3/v + 1/u = 4/u
1/f = 4/u
f = u/4
u = 4f
= 4×(32×10^-2)
= 1.28 m
Therefore the distance from the mirror to the object is 1.28 m.
part B:
v = 1/3×u = 1/3×(1.28) = 0.43 m
