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Effectus [21]
3 years ago
8

If f(x)=2x-6 and g(x)=x^3 what is (g f)(0)

Mathematics
1 answer:
marin [14]3 years ago
4 0

ANSWER

(g \circ \: f)(0) = - 216

EXPLANATION

The functions are:

f(x) = 2x - 6

g(x) =  {x}^{3}

(g \circ \: f)(x) =g(f(x))

(g \circ \: f)(x) =g(2x - 6)

We substitute f(x) into g(x) to obtain:

(g \circ \: f)(x) =(2x - 6)^{3}

We now substitute x=0 to obtain;

(g \circ \: f)(0) =(2(0) - 6)^{3}

(g \circ \: f)(0) =(- 6)^{3}

This simplifies to:

(g \circ \: f)(0) = - 216

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