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3 years ago

If f(x)=2x-6 and g(x)=x^3 what is (g f)(0)

Mathematics

1 answer:

marin [14]3 years ago

4 0

ANSWER

$(g \circ \: f)(0) = - 216$

EXPLANATION

The functions are:

$f(x) = 2x - 6$

$g(x) = {x}^{3}$

$(g \circ \: f)(x) =g(f(x))$

$(g \circ \: f)(x) =g(2x - 6)$

We substitute f(x) into g(x) to obtain:

$(g \circ \: f)(x) =(2x - 6)^{3}$

We now substitute x=0 to obtain;

$(g \circ \: f)(0) =(2(0) - 6)^{3}$

$(g \circ \: f)(0) =(- 6)^{3}$

This simplifies to:

$(g \circ \: f)(0) = - 216$

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$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)$

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$P(X \leq 1) + P(X > 1) = 1$

$P(X > 1) = 1 - P(X \leq 1)$

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