Answer:
3876
Step-by-step explanation:
Given the following :
Fraternity members = 20
They are to attend 5 different parties in groups of 4
Meaning a group = 4 persons
Atleast one brother will attend exactly one of the parties. (the brothers are indistinguishable).
Then, exactly one brother at a party (20 - 1) = 19, since they are indistinguishable.
Group members are in 4's
19C4
From: nCr = n! /(n-r)! r!
19C4 = 19! / (19 - 4)! 4!
= 19! / 15! 4!
= (19 * 18 * 17 * 16) / (4 * 3 * 2)
= 93024 / 24
= 3876
Answer: w= -10
Step-by-step explanation: move all terms not containing w to the right side of the equation
Its actually the same length. I will choose B so that i can run slower
<em>p</em> ² + 6 is even if <em>p</em> ² is even (the sum of two even numbers is even), and this happens only if <em>p</em> itself is even, i.e. if <em>p</em> = 2 since 2 is the only even prime.
All other primes <em>p</em> are odd, so <em>p</em> ² would be odd, and adding 6 would not change that (odd + even = odd).
