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Dvinal [7]
3 years ago
5

What's the product: (12x+1)(3x-8)

Mathematics
1 answer:
hram777 [196]3 years ago
7 0

Answer:

0000000000000000000

Step-by-step explanation:


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A rectangular prism is 7 cm long, 4 cm wide and 4 cm tall. How many 2 times 2 times 2 cm cubes can the prism be cut into? What i
Fantom [35]

Answer: The number of 2 times 2 times 2 cm cubes is 14. The total surface area of all the 2 times 2 times 2 times cm cubes is 336 cm square. The total volume of all the 2 times 2 times 2 times cm cubes is 112 cm cube.

Explanation:

It is given that the A rectangular prism is 7 cm long, 4 cm wide and 4 cm tall.

The volume of rectangular prism is,

V_1=l\times b\times h

V_1=7\times 4\times 4

V_1=112

Therefore, the volume of rectangular prism is 112 cm square.

The volume of cubes is,

V_2=a^3

V_2=(2)^3

V_2=8

The number of cubes in the rectangular prism is,

N=\frac{V_1}{V_2} =\frac{112}{8} =14

Therefore, the number of cubes is 14.

Total surface area of a cube is,

A=6a^2

A=6(2)^2

A=24

Total surface area of all cubes is,

14\times A=14\times 24=336

Therefore the total surface area of all cubes is 336 cm square.

Total volume of all cubes is equal t the volume of rectangular prism, i.e, 112 cm cube.

5 0
3 years ago
Katie runs 4 miles in 24 minutes. How many miles can she run in 30 minutes?
vova2212 [387]
Katie runs 1 mile every 6 mins so she can run 5 miles in 30 mins.
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3 years ago
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If x varies jointly as y and z , and x =8 when y = 4 and z=9, find z when x =16 and y =6
Likurg_2 [28]
X = 8 when y = 4 and z = 9, then k = x/(yz) = 8/(4*9) = 2/9. The equation is x = (2/9)yz. when x = 16 and y = 6, (2/9)*6*z = 16, solve the equation we get z = 12
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(05.02 MC)
tankabanditka [31]

Answer:

there is no value to x in this system because you don't have a number for the variable y

Step-by-step explanation:

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3 years ago
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Find the jacobian of the transformation. x = u2 + uv, y = uv2
atroni [7]
\mathbf J=\begin{bmatrix}\dfrac{\partial x}{\partial u}&\dfrac{\partial x}{\partial v}\\\\\dfrac{\partial y}{\partial u}&\dfrac{\partial y}{\partial v}\end{bmatrix}=\begin{bmatrix}2u+v&u\\v^2&2uv\end{bmatrix}

The Jacobian has determinant

\det\mathbf J=\begin{vmatrix}2u+v&u\\v^2&2uv\end{vmatrix}=(2u+v)2uv-uv^2=4u^2v+uv^2=uv(4u+v)
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