An electrician charges a service call fee of $60 plus $55 per hour. Another electrician charges a service call fee of $20 plus $
65 per hour. Set up and solve an equation to determine the number of hours, h, for which the cost would be the same for hiring both electricians.
2 answers:
Answer:
Step-by-step explanation:
Electrician A:
60+ 55h
You will pay the electrician $60 no matter what plus an additional $55 per hour, h
Electrician B:
20+ 65h
You will pay the electrician $20 no matter what and $65 per hour, h
Put the equations together in order to solve for h:
60+55h= 20+ 65h
40= 10h
h= 4
If you hire either electrician for four hours, you will pay the same amount, which is $280
Answer:
Equation:
y=55x+60
That is the equation for the first company.
y=65x+20
That is the equation for the secoond company.
Answer is (4,280), They will meet at 4 hours and the price will be $280.
Step-by-step explanation:
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Step-by-step explanation:
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Therefore, the solution is:
![\boxed{\int \sin 7x\, dx=-\frac{\cos 7x}{7}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cint%20%5Csin%207x%5C%2C%20dx%3D-%5Cfrac%7B%5Ccos%207x%7D%7B7%7D%7D)
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Answer:
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Step-by-step explanation:
• sorry i d k, I just got the ans on calculator