Find the number of CoCl2 units present in a 0.78 mol sample.

Chemistry

1 answer:

stich3 [128]2 years ago

5 0

$\qquad\qquad\huge\underline{{\sf Answer}}$

Here we go ~

1 mole of $\sf{ COCl_2}$ has 6.022 × 10²³ molecules of the given compound.

So, 0.78 mole of $\sf{COCl_2}$ will have ~

$\qquad \sf \dashrightarrow \: 0.78 \times 6.022 \times 10 {}^{23}$

$\qquad \sf \dashrightarrow \: \approx4.7 \times 10 {}^{23} \: \: \: molecules$

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