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Alborosie
3 years ago
5

Sasha placed a few objects one by one near a magnet. Only two of the objects Sasha placed moved toward the magnet. Which of the

following are most likely to be those two objects?
possible answer: 1. Aluminum foil and iron nails
2. Metal paper clip and iron nails
3. Rubber band and plastic spoon
4. Steel spoon and rubber band
Chemistry
2 answers:
kirza4 [7]3 years ago
5 0

Answer:

.

Explanation:

pentagon [3]3 years ago
5 0

Answer:

#2 Metal paper clip and iron nails

Explanation:

This is because they are both magnetic. Hope this helps. :)

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Which statement describes the masses of the particles that make up an atom?
ryzh [129]

<span>An atom is the smallest component of matter that keeps all of the chemical properties of an element. Atoms merge to form molecules, which then connect to form solids, gases, or liquids. Atoms are made up of three basic particles: protons, electrons, and neutrons. Atoms have different properties based on the order and number of their basic particles. Protons and neutrons have accurate mass, about 1.67x10 -24 grams.</span>

8 0
3 years ago
Balance the following redox equation in acidic solution using the smallest integers possible and select the correct coefficient
Evgen [1.6K]

Answer:

The balanced redox is:

14 H⁺ + Cr₂O₇²⁻ + 3Sn²⁺ → 3Sn4⁺  + 2Cr³⁺  + 7H₂O

So the coefficient for the H⁺ is greater than 4 (option E)

Explanation:

This is the redox reaction:

Cr₂O₇²⁻ (aq) + Sn²⁺ (aq)  →  Cr³⁺ (aq) + Sn⁴⁺(aq)

First of all, we must determine the half reactions:

In dycromate, Cr acts with +6 in the oxidation state → Cr cation has +3 in product side - Oxidation state, has decreased so this is the reduction.

In reactant side Sn cation acts with +2 → In product side Sn acts with +4

The oxidation state has increased, so this is the oxidation.

Cr₂O₇²⁻  → Cr³⁺

We have to add 2, to Cr in reactant side, and as we are in adicid medium we add water in the opposite side of oxygen. The same amount of oxgen, that we have.

Cr₂O₇²⁻  → 2Cr³⁺ + 7H₂O

Finally, as we have 14 H in product side, we must add 14 H⁺ to the reactant side. Cr+⁶ in dycromate to change to Cr³⁺, gained 3 e⁻, but we have 2 Cr, so in total the Cr gained 6e⁻. The balanced half reaction is:

14 H⁺ + Cr₂O₇²⁻ + 6e⁻ → 2Cr³⁺  + 7H₂O

Sn²⁺ to change the oxidation state, to +4 had to release electrons:

Sn²⁺ →  Sn4⁺  + 2e⁻

The electrons are unbalanced, so we must to multiply the half reactions:

(14 H⁺ + Cr₂O₇²⁻ + 6e⁻ → 2Cr³⁺  + 7H₂O) x1

(Sn²⁺ →  Sn4⁺  + 2e⁻ ) x3

And we sum both:

14 H⁺ + Cr₂O₇²⁻ + 6e⁻ + 3Sn²⁺ → 3Sn4⁺  + 6e⁻  + 2Cr³⁺  + 7H₂O

4 0
3 years ago
Please somone help me with a chemistry question brainliest to whoever answers correctly and 20 points
Zina [86]

Answer:

3132 is the answer

Explanation:

3BaCl2 + Al2S3 → 3BaS + 2AlCl3

3 0
3 years ago
Read 2 more answers
Write the simple equation that describes the action of the enzyme catalase.
Nataly [62]

Here we have to write a simple equation which describes the action of the enzyme catalase.

The equation is: The concentration of the complex [ES] = \frac{[E]0}{1+\frac{Km}{[S]} }

Let us consider an enzyme catalyses reaction E + S ⇄ ES → E + P

Where E, S, ES and P are enzyme, substrate, complex and product respectively.

The concentration of the complex [ES] = \frac{[E]0}{1+\frac{Km}{[S]} }, where K_{m} is the Michaelis constant.

[E]₀ and [S] is the initial concentration of enzyme and concentration of substrate respectively.    

5 0
3 years ago
The length breadth and thickness of a brick is 18cm 8 cm and 5cm respictively find the area of the widest part of rhe brick​
Sunny_sXe [5.5K]

Answer:

144cm²

Explanation:

Given dimensions:

     Length x breadth x thickness

        18cm  x   8cm    x    5cm

The widest part of this figure will be the face containing the length and the breadth.

The breadth is the width of the figure;

Area of the widest part  = length x breadth = 18cm x 8cm  = 144cm

The area of the widest part of the figure is 144cm²

4 0
3 years ago
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