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Elden [556K]
4 years ago
10

There are three basic methods of transmitting power as a. Electronical, mechanical, and fluid power b. Electical, mechanical, an

d chemical c. Electrical, mechanical, and fluid power d. Mechanical, pneumatic, and hydraulic power
Engineering
1 answer:
Elan Coil [88]4 years ago
6 0

Answer: C) Electrical, mechanical and fluid power

Explanation: The basic ways of transmitting power easily  are

Electrical power:-The transmission of power in the form f electricity is generated from the power using several resources. E.g.- power plant

Mechanical power :-The power that is obtained from the movement and forces using resources and obtain power in mechanical form.E.g.-engines

Fluid Power:-in this fluids are pressurized to generate the power and transmit it in the form of fluid power system .E.g.-hydraulic pump

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Neon is compressed from 100 kPa and 20◦C to 500 kPa in an isothermal compressor. Determine the change in the specific volume and
PIT_PIT [208]

Answer:

The specific volume is reduced in 80 per cent due to isothermal compression.

Specific enthalpy remains constant.

Explanation:

Let suppose that neon behaves ideally, the equation of state for ideal gases is:

P\cdot V = n\cdot R_{u}\cdot T

Where:

P - Pressure, measured in kilopascals.

V - Volume, measured in cubic meters.

n - Molar quantity, measured in kilomoles,

T - Temperature, measured in kelvins.

R_{u} - Ideal gas constant, measured in \frac{kPa\cdot m^{3}}{kmol\cdot K}.

On the other hand, the molar quantity (n) and specific volume (\nu), measured in cubic meter per kilogram, are defined as:

n = \frac{m}{M} and \nu = \frac{V}{m}

Where:

m - Mass of neon, measured in kilograms.

M - Molar mass of neon, measured in kilograms per kilomoles.

After replacing in the equation of state, the resulting expression is therefore simplified in term of specific volume:

P\cdot V = \frac{m}{M}\cdot R_{u}\cdot T

P\cdot \nu = \frac{R_{u}\cdot T}{M}

Since the neon is compressed isothermally, the following relation is constructed herein:

P_{1}\cdot \nu_{1} = P_{2}\cdot \nu_{2}

Where:

P_{1}, P_{2} - Initial and final pressure, measured in kilopascals.

\nu_{1}, \nu_{2} - Initial and final specific volume, measured in cubic meters per kilogram.

The change in specific volume is given by the following expression:

\frac{\nu_{2}}{\nu_{1}} = \frac{P_{1}}{P_{2}}

Given that P_{1} = 100\,kPa and P_{2} = 500\,kPa, the change in specific volume is:

\frac{\nu_{2}}{\nu_{1}} = \frac{100\,kPa}{500\,kPa}

\frac{\nu_{2}}{\nu_{1}} = \frac{1}{5}

The specific volume is reduced in 80 per cent due to isothermal compression.

Under the ideal gas supposition, specific enthalpy is only function of temperature, as neon experiments an isothermal process, temperature remains constant and, hence, there is no change in specific enthalpy.

Specific enthalpy remains constant.

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Answer:

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Explanation:

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A rocket is to be designed to produce 5 MN of thrust at sea level. The pressure in the combustion chamber is 7 MPa and the tempe
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Answer:

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