Question

How do you solve this

Answer 1

Answer:

Explanation:

You simply have to multiply it by the molar mass =

m = 50mol SnSO4 x 214.773 g/mol

m = 10.738 g SnSO4

Answer 2

Answer:

Mass of 50 moles of tin(II) sulfate is 10,738 grams.

Explanation:

$n=\frac{m}{M}$

Where:

n = moles of compound

m = mass of compound

M = molar mass of the compound

Moles of tin(II) sulfate , n= 50 moles

Molar mass of tin (II) sulfate , M= 214.77 g/mol

m = n × M

$m=50 moles \times 214.77 g/mol=10,738 g$

Mass of 50 moles of tin(II) sulfate is 10,738 grams.