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Bingel [31]
3 years ago
13

How do you solve this

Chemistry
2 answers:
denpristay [2]3 years ago
4 0

Answer:

Explanation:

You simply have to multiply it by the molar mass =

m = 50mol SnSO4 x 214.773 g/mol

m = 10.738 g SnSO4

Kruka [31]3 years ago
4 0

Answer:

Mass of 50 moles of tin(II) sulfate is 10,738 grams.

Explanation:

n=\frac{m}{M}

Where:

n = moles of compound

m = mass of compound

M = molar mass of the compound

Moles of tin(II) sulfate , n= 50 moles

Molar mass of tin (II) sulfate , M= 214.77 g/mol

m = n × M

m=50 moles \times 214.77 g/mol=10,738 g

Mass of 50 moles of tin(II) sulfate is 10,738 grams.

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A chemical engineer must calculate the maximum safe operating temperature of a high-pressure gas reaction vessel. The vessel is
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Answer:

the maximum safe operating temperature the engineer should recommend for this reaction is 616 °C  

Explanation:

Given the data in the question;

First we calculate the Volume of the steel cylinder;

V = πr²h

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so we substitute

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we know that;

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T = PV / nR

we know that gas constant R = 0.0820574 L•atm•mol⁻¹ K⁻¹

so we substitute

T = ( 30.5946 × 18.551 ) / ( 7.7829 × 0.082 )

T = 567.5604 / 0.6381978

T = 889.317387 K

T = ( 889.317387 - 273.15 ) °C

T = 616.167 ≈ 616 °C  { 3 significant digits }

Therefore, the maximum safe operating temperature the engineer should recommend for this reaction is 616 °C  

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