A) 1.55
The speed of light in a medium is given by:
where
is the speed of light in a vacuum
n is the refractive index of the material
In this problem, the speed of light in quartz is
So we can re-arrange the previous formula to find n, the index of refraction of quartz:
B) 550.3 nm
The relationship between the wavelength of the light in air and in quartz is
where
is the wavelenght in quartz
is the wavelength in air
n is the refractive index
For the light in this problem, we have
Therefore, we can re-arrange the equation to find , the wavelength in air:
Answer:
The value is 
Explanation:
Generally the moon's radial acceleration is mathematically represented as
Here 
is the angular velocity which is mathematically represented as
substituting 
for T(i.e the period of the moon ) we have
=> 
From the question r(which is the radius of the orbit ) is evaluated as
substitute 
for R and 
H
=> 
So
Answer:
exothermic change hope it help
Answer:
answer= 2.27 millisecond
Explanation:
Pitch of middle A corresponds to a frequency of 440 oscillation in 1 second.
we can write: A 440= oscillation/sec
440/sec = 440Hz
1/(440/sec)=(1/440)sec =0.00227sec
= 2.27milliseconds
Answer:
Uncertainty ΔV = 22.601 x 10^-10
ΔV = 2.2601nv or 2.2601 x 10^9V
Explanation:
from V = kQ/r
Uncertainty in V is given by δV = V square root [ (δQ/Q)^2 + (δr/r)^2]
ΔV = V square root [ (ΔQ/Q)^2 + (Δr/r)^2] .....................(2)
Given that ; Q = 3.2042e−19 C, r = 0.08 m, ΔQ = 1.6021e−21 C, Δr = 0.005 m
Plugging the values given into equation (2)
from ΔV =(kQ/r) square root [ (ΔQ/Q)^2 + (Δr/r)^2]
ΔV = 9 x 10^9 x 3.2042e−19 / 0.08 square root [ (1.6021e−21/ 3.2042e−19)^2 + ( 0.005/0.08)^2]
ΔV = 360.47 x 0.06269 x 10^-10
Uncertainty ΔV = 22.601 x 10^-10
ΔV = 2.2601nv or 2.2601 x 10^-9V
