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Kruka [31]
3 years ago
6

100 POINTS! I will mark brainliest! Record your hypothesis as an “if, then” statement for the rate of dissolving the compounds:

Record your hypothesis as an “if, then” statement for the boiling point of the compounds:
Physics
1 answer:
love history [14]3 years ago
6 0

Answer:

<u><em>Rate of dissolving compounds:</em></u>

If we increase the temperature of the solution, then the dissolving compound would dissolve more easily.

<u><em>Boiling Point of Compounds:</em></u>

If the inter-molecular forces of any compound is really strong, then the boiling point of the compound would be really high.

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A light wave travels through water (n = 1.33) at an angle of 35°. What angle
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Answer:1

Explanation:

1

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3 years ago
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Two small insulating spheres with radius 3.50×10−2 m are separated by a large center-to-center distance of 0.555 m. One sphere i
xz_007 [3.2K]

Answer:

E = 7.83 \times 10^5 N/C

Explanation:

Since we know that two sphere is oppositely charged so net electric field at the mid point of two balls will be sum of the electric field due to each ball at the mid point

So we know that

E = \frac{kq_1}{r^2} + \frac{kq_2}{r^2}

here we know that

q_1 = 4.20 \mu C

q_2 = 2.50 \mu C

r = \frac{0.555}{2}

so we have

E = \frac{(9\times 10^9)(4.20 + 2.50) \times 10^{-6}}{0.2775^2}

E = 7.83 \times 10^5 N/C

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2 years ago
What is one measurement needed to calculate the speed of an object? Direction Mass Time Velocity
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The answer is Time.

Formula: Distance/Time

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3 years ago
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A 16 V battery does 1705 J of work transferring charge. How much charge is transferred? Answer in units of C.
vladimir1956 [14]

Answer:

Explanation:

Given

Voltage V=16\ V

Work done W=1705\ J

Work is Equivalent to energy

We know that Charge is given by

Q=I\cdot t

where I=current

t=time

Energy E=P\times t

P=power

P=V\times I

V=Voltage

I=current

Also Energy E=V\cdot I\cdot t

I=\frac{E}{V\cdot t}

Substitute the value of I in charge

Q=\frac{E}{V\cdot t}\times t

Q=\frac{E}{V}

Q=\frac{1705}{16}

Q=106.56\ C        

5 0
3 years ago
Coherent light with wavelength 597 nm passes through two very narrow slits, and theinterference pattern is observed on a screen
velikii [3]

Answer:

The required wavelength is 1.19 μm

Explanation:

In the double-slit study, the formula below determines the position of light fringes y_m on-screen.

y_m = \dfrac{m \lambda D}{d}

where;

m = fringe order

d = slit separation

λ = wavelength

D = distance between screen to the source

For the first bright fringe, m = 1, and we make (d) the subject, we have:

d = \dfrac{(1) \lambda D}{y_1}

d = \dfrac{ \lambda D}{y_1}

replacing the value from the given question, we get:

d = \dfrac{ (597 \ nm )\times (3.00 \  m)}{4.84 \ mm} \\ \\ d = \dfrac{ (597 \ nm \times (\dfrac{1 \ m}{10^9\ nm}) )\times (3.00 \  m)}{4.84 \ mm(\dfrac{1 \ m}{1000 \ mm })} \\ \\  d = 3.7 \times 10^{-4}  \ m

In the double-slit study, the formula which illustrates the position of dark fringes y_m on-screen can be illustrated as:

y_m = (m+\dfrac{1}{2}) \dfrac{\lambda D}{d}

The value of m in the dark fringe first order = 0

∴

y_0 = (0+\dfrac{1}{2}) \dfrac{\lambda D}{d}

y_0 = (\dfrac{1}{2}) \dfrac{\lambda D}{d}

making λ the subject of the formula, we have:

\lambda = \dfrac{2y_o d}{D} \\ \\ \lambda = \dfrac{2(4.84 \  mm) \times \dfrac{1 \ m}{1000 \ mm} (3.7 \times 10^{-4}  \ m) }{3.00 \ m}

\lambda = 1.19 \times 10^{-6}  \ m ( \dfrac{10^6 \mu m }{1\ m}) \\ \\ \lambda = 1.19 \mu m

5 0
2 years ago
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