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Naya [18.7K]
3 years ago
9

Since 2002, the number of a telephone company’s customers using a landline has been decreasing by 10% per year. Which of these s

tatements are correct? Select all that apply.
1. To find the number of landline customers in 2004, you can multiply the number of landline customers in 2002 by 0.81.
2. To find the number of landline customers in 2004, you can subtract the product of 0.2 and the number of landline customers in 2002 from the number of landline customers in 2002.
3. To find the number of landline customers in 2003, you can multiply the number of landline customers in 2002 by 0.9
4. To find the number of landline customers in 2003, you can subtract the product of 0.1 and number of landline customers in 2002 from the number of landline customers in 2002.
Mathematics
2 answers:
Alex3 years ago
8 0

Answer:

Option 1 , Option 3 and Option 4 are correct.

Step-by-step explanation:

Number of customers using landlines decreases 10% per year.

Let x be the umber of customers using landlines in 2002.

⇒ Number of customer using landlines in 2003 = x-\frac{10}{100}\times x

                                                                               = x-0.1x

                                                                               = 0.9x

Number of customers using landlines in 2004 =  0.9x-\frac{10}{100}\times 0.9x

                                                                              = 0.9x-0.1\times0.9x

                                                                              = 0.9x-0.09x

                                                                              = 0.81x

Therefore, from this Option 1 , Option 3 and Option 4 are correct.

prohojiy [21]3 years ago
7 0

1 and 3 I believe are the correct answers

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Answer:

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\left[\begin{array}{cccc}0&1&1&1\\0&0&1&1\\0&0&0&1\\0&0&0&0\end{array}\right]

for b

b) {(1, 1), (1, 4), (2, 2), (3, 3), (4, 1)}

\left[\begin{array}{cccc}1&0&0&1\\0&1&0&0\\0&0&1&0\\1&0&0&0\end{array}\right]

for c) {(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)}

\left[\begin{array}{cccc}0&1&1&1\\1&0&1&1\\1&1&0&1\\1&1&1&0\end{array}\right]

for d d) {(2, 4), (3, 1), (3, 2), (3, 4)}

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Step-by-step explanation:

in matrix, arrays are placed in rows , which represents the horizontal sides from left to right, while arrays in the column are placed vertically from top to bottom. Here, we placed the arrays in a 4x4 matrix

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\left[\begin{array}{cccc}1&0&0&1\\0&1&0&0\\0&0&1&0\\1&0&0&0\end{array}\right]

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\left[\begin{array}{cccc}0&1&1&1\\1&0&1&1\\1&1&0&1\\1&1&1&0\end{array}\right]

for d d) {(2, 4), (3, 1), (3, 2), (3, 4)}

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4 years ago
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Answer:

The Amin's score in math was 46.

Step-by-step explanation:

The question is:

The average math score for Amin, azman and aziz is 73. Azman marks 35 more than Amin while aziz is twice that of Amun. What is Amin's sign?

Solution:

Let us denote that:

<em>x</em> = Amin's score in math

<em>y</em> = Azman's score in math

<em>z</em> = Aziz's score in math.

The average of <em>x</em>, <em>y</em> and <em>z</em> is, 73.

That is:

\frac{x+y+z}{3}=73\\\\\Rightarrow x+y+z = 219

Now it is provided that:

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Answer:

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Step-by-step explanation:

When the standard deviations are not the same then the confidence intervals for mean differences are calculated as

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x1`= 21        x2`= 27

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The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

The t∝/2 for 17 d.f = 2.11

Putting the values

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6- 2.11*2.111 < u1-u2 <  ( 6 )  +2.11*2.111

6- 4.4521 < u1-u2 <  ( 6 )  +5.294

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a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

The claim is that there is a difference in the average time spent by the two services

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

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υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

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t= (x1`-x2`)  /√s1²/n1 + s2²/n2

t= (21-27)  /√5.6²/10+ 4.3²/14

t= -6/2.111

t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

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Step-by-step explanation:

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For 4 Packets he needs to pay £2.52

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