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777dan777 [17]
3 years ago
11

1) The temperature inside my refrigerator is about 40 Celsius. If I place a balloon in my fridge that initially has a temperatur

e of 220 C and a volume of 0.5 liters, what will be the volume of the balloon when it is fully cooled by my refrigerator?
Chemistry
1 answer:
viva [34]3 years ago
4 0

Answer:  The volume of the balloon when it is fully cooled by my refrigerator is 0.3 L

Explanation:

To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=0.5L\\T_1=220^oC=(220+273)K=493K\\V_2=?\\T_2=40^oC=(40+273)K=313K

Putting values in above equation, we get:

\frac{0.5}{493}=\frac{V_2}{313}\\\\V_2=0.3

Thus the volume of the balloon when it is fully cooled by my refrigerator is 0.3 L

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Copper sulfate is a blue solid that is used to control algae growth. Solutions of copper sulfate that come in contact with the s
True [87]

Answer:

185.49 grams of Zinc would react with 454g (1lb) of copper sulfate

Explanation:

Yo know the following balanced reaction:

CuSO₄(aq)+ Zn(s) →Cu(s) + ZnSO₄(aq)

You can see that by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reagents and products are part of the reaction:

  • CuSO₄: 1 mole
  • Zn: 1 mole
  • Cu: 1 mole
  • ZnSO₄: 1 mole

Being:

  • Cu: 63.54 g/mole
  • S: 32 g/mole
  • O: 16 g/mole
  • Zn: 65.37 g/mole

the molar mass of the compounds participating in the reaction is:

  • CuSO₄:63.54 g/mole + 32 g/mole + 4*16 g/mole= 159.54 g/mole ≅ 160 g/mole
  • Zn: 65.37 g/mole
  • Cu: 63.54 g/mole
  • ZnSO₄: 65.37 g/mole + 32 g/mole + 4*16 g/mole= 161.37 g/mole

Then, by stoichiometry of the reaction, the following amounts of mass of reagent and product participate in the reaction:

  • CuSO₄: 1 moles* 160 g/mole= 160 g
  • Zn: 1 mole* 65.37 g/mole= 65.37 g
  • Cu: 1 mole* 63.54 g/mole= 63.54 g
  • ZnSO₄: 1 mole* 161.37 g/mole= 161.37 g

Now you can apply the following rule of three: if 160 grams of CuSO₄ react with 65.37 grams of Zn by this reaction stoichiometry, 454 grams of CuSO₄ with how much mass of Zn will it react?

mass of Zn=\frac{454 grams of CuSO_{4} *65.37 grams of Zn}{160 grams of CuSO_{4}}

mass of Zn= 185.49 grams

<u><em>185.49 grams of Zinc would react with 454g (1lb) of copper sulfate</em></u>

4 0
3 years ago
when you started the activity, the can was open to the air outside tge can. how did the air pressure inside the can compare to t
aliya0001 [1]

The air pressure inside the can is lower compared to that of outside air pressure.

Explanation:

  • In general, the air pressure of an already opened can will be the same as the outside pressure.
  • Since the can is evacuated and remain as vacuum, so there will be no pressure difference in it.
  • If the can opens, air inside the can push the top and escapes to the outside.
  • This is due to high pressure experienced outside the can compare to that of lower pressure inside the can and this may even cause can to collapse itself.
7 0
3 years ago
Determine the pH of a 2.8 ×10−4 M solution<br> of Ca(OH)2.
shepuryov [24]

Answer:

pH = 10.75

Explanation:

To solve this problem, we must find the molarity of [OH⁻]. With the molarity we can find the pOH = -log[OH⁻]

Using the equation:

pH = 14 - pOH

We can find the pH of the solution.

The molarity of Ca(OH)₂ is 2.8x10⁻⁴M, as there are 2 moles of OH⁻ in 1 mole of Ca(OH)₂, the molarity of [OH⁻] is 2*2.8x10⁻⁴M = 5.6x10⁻⁴M

pOH is

pOH = -log 5.6x10⁻⁴M

pOH = 3.25

pH = 14-pOH

<h3>pH = 10.75</h3>
3 0
3 years ago
How many objects are in a mole of objects?
lakkis [162]
Your Question: {How many objects are in a mole?}

Helpful Knowledge: (We Know the amount in an object: 12g or C^12)

{A number of objects that are in a mole of objects?}

Well for the question it is pretty easy to answer because a number of objects in One mole would equal 6.02 × 10²³ 

Which 6.02 × 10²³ is an Avogadro's Number. 

So it depends on how many objects you have.

So for every object you have, One mole would equal 6.02 × 10²³. Or 62,000,000,000,000,0000,000,000. Big Number am I right. So that's why we just use 6.02 × 10²³.

Anywho, your answer would be 6.02 x 10²³ x n. 
N would equal the number of objects you're calculating. 

Final Answer: 6.02 x 10²³ x (n) = (Your Answer)

Hope this helps! Have a great day. If you need anything else, feel free to hope right in my inbox. Or comment below. ↓

6 0
3 years ago
What is the mass, in grams, of 50.0L of N2 at STP?
vodka [1.7K]

Hey there!:

Molar mass N₂ = 28.0134 g/mol

28.0134 g ------------------- 22.4 L (at STP )

mass  N₂ -------------------- 50.0 L

mass N₂ = 50.0 x 28.0134 / 22.4

mass N₂ = 1400.67 / 22.4

mass N₂ = 62.529 g

Hope this helps!

6 0
3 years ago
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