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Blizzard [7]
2 years ago
15

How many micrometers are in 1.25 miles. Tell me how you got that answer as well.​

Chemistry
1 answer:
Oliga [24]2 years ago
5 0

Answer:

10, 100, 1,000, etc., as well as 0.1, 0.01, 0.001, etc

Explanation:

You might be interested in
What coefficient is needed to balance the reaction
tensa zangetsu [6.8K]

Answer:

OD. 2HCl

Explanation:

A balanced equation needs the equal # of each element on BOTH sides.

By putting a 2 in front of HCl you now have 2 hydrogens on both sides and 2 chlorines. The Ca and CO3 are already balanced.

5 0
2 years ago
Boyle’s law states that the volume of a gas is inversely proportional to its pressure if the
nasty-shy [4]

Boyle's law states that the volume of a fixed mass of a gas is inversely proportional to its temperature if<u> the temperature and the number of particles are constant.</u>

<h3>Further Explanation</h3><h3>Boyles’s law  </h3>
  • This gas law states that the volume of a fixed mass of a gas is inversely proportional to its pressure at constant absolute temperature.
  • Therefore, when the volume of an ideal gas is increased at constant temperature then the pressure of the gas will also increase.
  • Mathematically;  Volume α 1/Pressure

                               Vα1/P

  • Therefore, constant k, is = PV
<h3>Other gas Laws</h3><h3>Gay-Lussac’s law  </h3>
  • It states that at constant volume, the pressure of an ideal gas I directly proportional to its absolute temperature.
  • Thus, an increase in pressure of an ideal gas at constant volume will result to an increase in the absolute temperature.
<h3>Charles’s law</h3>
  • It states that the volume of a fixed mass of a gas is directly proportional to absolute temperature at constant pressure.
  • Therefore, an increase in volume of an ideal gas causes a corresponding increase in its absolute temperature and vice versa while the pressure is held constant.
<h3>Dalton’s law  </h3>
  • It is also known as the Dalton’s law of partial pressure. It states that the total pressure of a mixture of gases is always equivalent to the total sum of the partial pressures of individual component gases.
  • Partial pressure refers to the pressure of an individual gas if it occupies the same volume as the mixture of gases.

Keywords: Gas law, Boyles's law, pressure, volume, absolute temperature, ideal gas

<h3>Learn more about:</h3>
  • Boyles’s law: brainly.com/question/2438000
  • Gay-Lussac’s law: brainly.com/question/2438000
  • Charles’s law:brainly.com/question/2438000
  • Dalton’s law:brainly.com/question/2438000

Level: High school

Subject: Chemistry

Topic: Gas laws

Sub-topic: Boyle's Law  

3 0
3 years ago
Read 2 more answers
What is the osmolarity of a solution made by dissolving 0.50 mole of the strong electrolyte cacl2 in 1.0 l of solution?
valina [46]
Osmolarity=osmole  of  the  solute/litres  of  the  solution
ionic  equation  for  dissociation  of  CaCl2  is
CaCl2--->Ca2+   +2Cl-
total osmoles  for  reaction are    1(Ca2+)  + 2(Cl-)= 3 osmoles
therefore
 
0.50 moles of  CaCl2  x 3 osmoles/ 1mole of  CaCl2 = 1.5osmoles
osmolarity=1.5 /1.0  L=1.5 osmol/l
6 0
3 years ago
What is the name of the the following formula Cd(HOOCCOO)2
Andreyy89

Answer:

I think that is called oxalic acid

Explanation:

4 0
2 years ago
Now consider the reaction a+2b⇌c for which in the initial mixture qc=[c][a][b]2=387 is the reaction at equilibrium? if not, in w
Paul [167]
Solving this chemistry is a little bit hard because the question didn't give some important detailed. 
So first, there are a couple problems with your question. 
We will just need to know which direction will it proceed to reach equilibrium.
Your expression for Kc (and Qc ) for the reaction should be: 
Kc = [C] / [A] [B]^2 
You have not provided a value for Kc, so a value of Qc tells you absolutely nothing. Qc is only valuable in relation to a numerical value for Kc. If Qc = Kc, then the reaction is at equilibrium. If Q < K, the reaction will form more products to reach equilibrium, and if Q > Kc, the reaction will form more reactants.
5 0
3 years ago
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