The speed of the archerfish immediately after it expels the drop of water is about (b) 0.012 m/s

<h3>Further explanation</h3>
Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

F = Force ( Newton )
m = Object's Mass ( kg )
a = Acceleration ( m )
Let us now tackle the problem !

<em><u>The Question:</u></em>
<em>What is the speed of the archerfish immediately after it expels the drop of water? </em>
<em>(a) 0.0025 m/s; </em><em>(b) 0.012 m/s</em><em>; (c) 0.75 m/s; (d) 2.5 m/s.</em>
<u>Given:</u>
mass of fish = m₁ = 65 g
mass of drop of water = m₂ = 0.30 g
speed of water = v₂ = 2.5 m/s
initial speed of water = initial speed of archerfish = u₁ = u₂ = 0 m/s
<u>Asked:</u>
the speed of the archerfish = v₁ = ?
<u>Solution:</u>
<em>We will use </em><em>Conservation of Momentum Law </em><em>as follows:</em>







<h3>Conclusion :</h3>
<em>The speed of the archerfish immediately after it expels the drop of water is about </em><em>0.012 m/s</em>

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<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Dynamics