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3 years ago

HELP ME PLEASE!! 40 POINTS!

Mathematics

1 answer:

Anastasy [175]3 years ago

6 0

Answer:

2x+2y<_16 is the answer

Step-by-step explanation:

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3x^2+42x+105=0 Find the solution 0 0

Nina [5.8K]

Step-by-step explanation:

I think we have to find the factors so

3x2 + 42x + 105

First we will multiply 105 by 3 = 315 then find factors of 315 which may add or subtract = 42

So 45 and 7

3x2 + 45x - 7x + 105

3x( x + 15) - 7(x - 15)

(3x - 7) and ( x - 15) are the factors

There is a problem please recheck the question

6 0

3 years ago

A side of the triangle below has been extended to form an exterior angle of 132°. Find the value of X

Zinaida [17]

Answer:

x = 114°

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles, thus

x + 18° = 132° ( subtract 18° from both sides )

x = 114°

7 0

3 years ago

Travis sketches a scale drawing of his favorite race car. The scale he uses is 1 centimeter equals 1/4 foot. If the length of th

kirill [66]

16 because 1= 1 x 1/4 foot so 64= 64 x 1/4 foot

4 0

3 years ago

Read 2 more answers

6% as ratio in simplest form.

Kitty [74]

Answer:

3 : 50

Step-by-step explanation:

6% = 0.06

0.06 = 6/100

6/100 = 3/50

3/50 = 3 : 50

6 0

3 years ago

Try to sketch by hand the curve of intersection of the parabolic cylinder y = x2 and the top half of the ellipsoid x2 + 7y2 + 7z

vovikov84 [41]

Plug $y=x^2$ into the equation of the ellipsoid:

$x^2+7(x^2)^2+7z^2=49$

Complete the square:

$7x^4+x^2=7\left(x^4+\dfrac{x^2}7+\dfrac1{14^2}-\dfrac1{14^2}\right)=7\left(x^2+\dfrac1{14}\right)^2+\dfrac1{28}$

Then the intersection is such that

$7\left(x^2+\dfrac1{14}\right)^2+7z^2=\dfrac{1371}{28}$

$\left(x^2+\dfrac1{14}\right)^2+z^2=\dfrac{1371}{196}$

which resembles the equation of a circle, and suggests a parameterization is polar-like coordinates. Let

$x(t)^2+\dfrac1{14}=\sqrt{\dfrac{1371}{196}}\cos t\implies x(t)=\pm\sqrt{\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}}$

$y(t)=x(t)^2=\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}$

$z=\sqrt{\dfrac{1371}{196}}\sin t$

(Attached is a plot of the two surfaces and the intersection; red for the positive root $x(t)$ , blue for the negative)

4 0

4 years ago