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olasank [31]
2 years ago
8

What mass of F2 is needed to produce 180 g of PF3 if the reaction has a 78.1% yield?

Chemistry
1 answer:
nexus9112 [7]2 years ago
6 0

Answer:

91.26 g

Explanation:

Given data:

Mass of PF₃ = 180 g

Mass of F₂ required = ?

Solution:

Chemical equation:

P₄ + 6F₂   → 4PF₃

Moles of PF₃:

Number of moles = mass/ molar mass

Number of moles = 180 g/ 88 g/mol

Number of moles = 2.05 mol

Now we will compare the moles of PF₃ with F₂.

                        PF₃            :           F₂

                          4               :           6

                          2.05         :           6/4×2.05 = 3.075

Mass of  F₂:

Mass of F₂ = moles × molar mass

Mass of F₂ = 3.075 mol × 38 g/mol

Mass of F₂ =  116.85 g

If reaction yield is 78.1%:

116.85 /100 ×78.1 = 91.26 g

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Explanation:

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  Information about helium:

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  To write an atom we use this format:

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Every atom contains protons, neutrons and electrons;

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   neutrons do not have charges.

 

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helium brainly.com/question/2439349

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