Answer:
the light will reflect parallel to the principal axis
C. Hypothesis
The hypothesis is presented as an explanation of the observed results.
When we see the words "Which statement ... ", we know right away that there
will be a list of choices, and we're expected to select our answer from that list.
Strangely, the list of answer-choices for this question has been lost.
Similarly, when we see the words "The picture shows ... ", it's hard to fight
the impulse to look around. In the present situation, <em>that's</em> missing too.
If the diver is just standing there, then the reaction force provided by the cliff
against his feet must be exactly equal to his weight. If the vertical forces acting
on the soles of his feet were not balanced, then his feet would be accelerating
vertically.
His weight is (mass) x (gravity) =
(93 kg) x (9.8 m/s²) = <em>911.4 newtons</em> (about 205 pounds) .
That's also the strength of the upward reaction force provided by the cliff.
Answer:
-There are no other charges nearby.
Explanation:
-There are no other charges nearby.
If there is no net charge in nearby space then the force on this charge will be ZERO
-If there are other charges nearby, they must all have the same sign as Q.
There there is nearby charge of same sign then it will have repulsion force on Q
-If there are other charges nearby, they must all have the opposite sign of Q.
if there is nearby charge of opposite sign then the force must be attraction force.
-If there are other charges nearby, the total positive charge must equal the total negative charge.
If there exist two type of charges nearby then there may exist either attraction or repulsion force on it
Answer:
<em>Magnitude of frictional force = 30 N</em>
Explanation:
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
Fn=m.a
The net force is the vector addition of each individual force. If the sum of all the forces acting on an object is zero, then the acceleration is zero. That means the object moves at a constant speed or is at rest.
When an object is pushed across a horizontal rough surface, there are two forces acting in the direction of the motion: The applied force and the frictional force.
If the applied force is greater than the frictional force, then the object moves at a constant positive acceleration. If the frictional force is greater than the applied force, then the object won't move at all (if it was at rest) or will start a deaccelerated motion (braking).
Finally, if both forces are equal, the object will move at a constant speed or remains at rest. Since the box is moving at a constant speed, we can conclude the frictional force equals the applied force:
Magnitude of frictional force = 30 N