Answer:
C ) 1.53
Explanation:
The critical angle of a material is given by the formula
where
c is the critical angle
n is the refractive index
This formula is valid if the second medium is air (which is the case of the problem).
In this problem, we know the critical angle:
Therefore we can rearrange the equation to find the refractive index:
Answer:
The angle of projection is 12.26⁰.
Explanation:
Given;
initial position of the dart, h₀ = 1.50 m
height above the ground reached by the dart, h₁ = 1.73 m
maximum height reached by the dart, Hm = h₁ - h₀ = 1.73 m - 1.50 m= 0.23 m
velocity of the dart, u = 10 m/s
The maximum height reached by the projectile is calculated as;
where;
θ is angle of projection
g is acceleration due to gravity = 9.8 m/s²
Therefore, the angle of projection is 12.26⁰.