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inessss [21]
4 years ago
11

A charge Q experiences no net force at a particular point in space. Which of the following situations described below must ALWAY

S be true?
-There are no other charges nearby.

-If there are other charges nearby, they must all have the same sign as Q.

-If there are other charges nearby, they must all have the opposite sign of Q.

-If there are other charges nearby, the total positive charge must equal the total negative charge.

-None of the Above
Physics
1 answer:
laila [671]4 years ago
8 0

Answer:

-There are no other charges nearby.

Explanation:

-There are no other charges nearby.

If there is no net charge in nearby space then the force on this charge will be ZERO

-If there are other charges nearby, they must all have the same sign as Q.

There there is nearby charge of same sign then it will have repulsion force on Q

-If there are other charges nearby, they must all have the opposite sign of Q.

if there is nearby charge of opposite sign then the force must be attraction force.

-If there are other charges nearby, the total positive charge must equal the total negative charge.

If there exist two type of charges nearby then there may exist either attraction or repulsion force on it

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According to the Law of Universal Gravitation, which scenario would generate the most
ehidna [41]

Answer:

im not 100 percent but its probably 2 turtles 20m apart

3 0
3 years ago
A beam of protons moves in a circle of radius 0.20 m. The protons move perpendicular to a 0.36-T magnetic field. (a) What is the
gregori [183]

Answer:

a) v=6.898\times 10^{6}\ m.s^{-1} is the speed of each proton

b) F_c=3.97\times 10^{-13}\ N

Explanation:

Given:

radius of path of motion, r=0.2\ m

we know charge on protons, q=1.6\times 10^{-19}\ C

magnetic field strength, B=0.36\ T

we've mass of proton, m=1.67\times 10^{-27}\ kg

a)

From the equivalence of magnetic force and the centripetal force on the proton:

F_B=F_C

q.v.B=\frac{m.v^2}{r}

q.B=\frac{m.v}{r}

where:

v = speed of the proton

(1.6\times 10^{-19})\times 0.36=\frac{1.67\times 10^{-27}\times v}{0.2}

v=6.898\times 10^{6}\ m.s^{-1} is the speed of each proton

b)

Now the centripetal force on each proton:

F_c=m.\frac{v^2}{r}

F_c=1.67\times 10^{-27}\times \frac{(6.898\times 10^6)^2}{0.2}

F_c=3.97\times 10^{-13}\ N

6 0
4 years ago
A proton travels with a speed of 1.8×106 m/s at an angle 53◦ with a magnetic field of 0.49 T pointed in the +y direction. The ma
Likurg_2 [28]

Answer:

Magnetic force, F=1.12\times 10^{-13}\ N

Explanation:

It is given that,

Velocity of proton, v=1.8\times 10^6\ m/s

Angle between velocity and the magnetic field, θ = 53°

Magnetic field, B = 0.49 T

The mass of proton, m=1.672\times 10^{-27}\ kg

The charge on proton, q=1.6\times 10^{-19}\ C

The magnitude of magnetic force is given by :

F=qvB\ sin\theta

F=1.6\times 10^{-19}\ C\times 1.8\times 10^6\ m/s\times 0.49\ Tsin(53)

F=1.12\times 10^{-13}\ N

So, the magnitude of the magnetic force on the proton is 1.12\times 10^{-13}\ N. Hence, this is the required solution.

3 0
4 years ago
How can you make the potential energy as high as possible in a magnetic field between one electromagnet and one piece of iron?
harkovskaia [24]

In step 1, to increase the potential energy, the iron will move towards the electromagnet.

In step 2, to increase the potential energy, the iron will move towards the electromagnet.

<h3>Potential energy of a system of magnetic dipole</h3>

The potential energy of a system of dipole depends on the orientation of the dipole in the magnetic field.

U = \mu B

where;

  • \mu is the dipole moment
  • B is the magnetic field

B = \frac{\mu_0 I}{2\pi r}

U = \mu\times  (\frac{\mu_0 I}{2\pi r} )

Increase in the distance (r) reduces the potential energy. Thus, we can conclude the following;

  • In step 1, to increase the potential energy, the iron will move towards the electromagnet.
  • In step 2, when the iron is rotated 180, it will still maintain the original position, to increase the potential energy, the iron will move towards the electromagnet.

Learn more about potential energy in magnetic field here: brainly.com/question/14383738

7 0
2 years ago
A frequency generator sends a 550 Hz sound wave through both water and ice. What is the difference in wavelength between the wav
viva [34]
3.1m is the answer your looking for
5 0
3 years ago
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