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inessss [21]
4 years ago
11

A charge Q experiences no net force at a particular point in space. Which of the following situations described below must ALWAY

S be true?
-There are no other charges nearby.

-If there are other charges nearby, they must all have the same sign as Q.

-If there are other charges nearby, they must all have the opposite sign of Q.

-If there are other charges nearby, the total positive charge must equal the total negative charge.

-None of the Above
Physics
1 answer:
laila [671]4 years ago
8 0

Answer:

-There are no other charges nearby.

Explanation:

-There are no other charges nearby.

If there is no net charge in nearby space then the force on this charge will be ZERO

-If there are other charges nearby, they must all have the same sign as Q.

There there is nearby charge of same sign then it will have repulsion force on Q

-If there are other charges nearby, they must all have the opposite sign of Q.

if there is nearby charge of opposite sign then the force must be attraction force.

-If there are other charges nearby, the total positive charge must equal the total negative charge.

If there exist two type of charges nearby then there may exist either attraction or repulsion force on it

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Explanation:

From the question we are told that

   The angular speed of CD is  w_{CD} =  500 rpm =  \frac{500  rpm}{\frac{60 \ s }{1 \ min} } * \frac{2 \pi }{ 1 \ rev} = 52.37 rad/s

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The angular acceleration is mathematically represented as

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substituting values

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         a =  - 20.14 rad/s^2

The negative sign show that the CD is decelerating  but the magnitude is

       a =  20.14 rad/s^2

   

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