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nalin [4]
3 years ago
15

A company wants to develop audio speakers using an inexpensive type of plastic that has a very high quality of sound output. Whi

ch customers would most likely give a high evaluation of this product?
A. those who want to save money and will use the product for only a few years
B. those who want a top-quality product no matter how much it costs
C. those who want to save money and use the speakers for a long time
D. those who want a long-lasting product and are willing to pay a high price
Chemistry
1 answer:
olga nikolaevna [1]3 years ago
6 0

Answer:

a

Explanation:

Just took the test

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The circumference of a circle is 6.28 millimeters. What is the circle's diameter?
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3 years ago
10.0 grams of octane are burned in a bomb calorimeter containing 2.00 × 102 g H2O. How much energy, in kilocalories, is released
vodomira [7]
<span>you wanna use q=m*C*\Delta T\;

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4 years ago
How do I solve this?
Xelga [282]

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Explanation:

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7.95/6.02 = 1.32

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7 0
3 years ago
For a particular reaction at 235.8 °C, ΔG=−936.92 kJ/mol , and ΔS=513.79 J/(mol⋅K) . Calculate ΔG for this reaction at −9.9 °C.
Rudik [331]

Answer:

-138.9 kJ/mol

Explanation:

Step 1: Convert 235.8°C to the Kelvin scale

We will use the following expression.

K = °C + 273.15 = 235.8°C + 273.15 = 509.0 K

Step 2: Calculate the standard enthalpy of reaction (ΔH°)

We will use the following expression.

ΔG° = ΔH° - T.ΔS°

ΔH° = ΔG° / T.ΔS°

ΔH° = (-936.92kJ/mol) / 509.0K × 0.51379 kJ/mol.K

ΔH° = -3.583 kJ (for 1 mole of balanced reaction)

Step 3: Convert -9.9°C to the Kelvin scale

K = °C + 273.15 = -9.9°C + 273.15 = 263.3 K

Step 4: Calculate ΔG° at 263.3 K

ΔG° = ΔH° - T.ΔS°

ΔG° = -3.583 kJ/mol - 263.3 K × 0.51379 kJ/mol.K

ΔG° = -138.9 kJ/mol

8 0
3 years ago
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