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e-lub [12.9K]
3 years ago
6

What is the net ionic equation for the reaction of hydrochloric acid with potassium hydroxide?

Chemistry
1 answer:
ruslelena [56]3 years ago
3 0
The net ionic equation may be obtained from the reaction equation as follows:
HCl in solution is: H⁺ + Cl⁻
KOH in solution is: K⁺ + OH⁻
KCl in solution is: K⁺ + Cl⁻

H⁺ + Cl⁻ + K⁺ + OH⁻ → K⁺ + Cl⁻ + H₂O
Cancelling terms that are repeated on both sides,

H⁺ + OH⁻ → H₂O
This is the net ionic equation. Moreover, this equation holds true for all neutralization reactions.
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Calculate the dissociation constant of nh4oh(aq) if the degree of dissociation of 0.006 mol/kg solution is 0.053 and the activit
Anastasy [175]

The dissociation equation will be

                         NH4OH   --->        NH4+                   + OH-

Initial                 0.006                        0                          0

Change         -0.006 X 0.053        +0.006 X 0.053      -0.006 X 0.053

Equlibrium     0.006 -0.006 X 0.053      0.006 X 0.053    0.006 X 0.053

Ka = [NH4+] [ OH-] / [NH4OH] = (0.006 X 0.053)^2 / 0.006 -0.006 X 0.053

Ka = 1.78 X 10^-5

7 0
3 years ago
How many atoms are in 68.44 grams
creativ13 [48]
Correct answer There are 68 grams are in atoms
3 0
3 years ago
Urea, (NH2)2CO, is a product of metabolism of proteins. An aqueous solution is 37.2% urea by mass and has a density of 1.032 g/m
Feliz [49]

Answer:

The molarity of urea in this solution is 6.39 M.

Explanation:

Molarity (M) is <em>the number of moles of solute in 1 L of solution</em>;  that is

molarity = moles of solute ÷ liters of solution

To calculate the molality, we need to know the number of moles of urea and the volume of solution in liters. We assume 100 grams of solution.

Our first step is to calculate the moles of urea in 100 grams of the solution,

using the molar mass a conversion factor. The total moles of 100g of a 37.2 percent by mass solution is

60.06 g/mol ÷ 37.2 g = 0.619 mol

Now we need to calculate the volume of 100 grams of solution, and we use density as a conversion factor.

1.032 g/mL ÷ 100 g = 96.9 mL

This solution contains 0.619 moles of urea in 96.9 mL of solution. To express it in molarity, we need to calculate the moles present in 1000 mL (1 L) of the solution.

0.619 mol/96.9 mL × 1000 mL= 6.39 M

Therefore, the molarity of the solution is 6.39 M.

4 0
4 years ago
Is a oreo a pure substance or a mixture
adoni [48]
Belive it or not but an oreo is a mixture. LOL
7 0
3 years ago
if the half-life of substance A is 1.5 years, how long would it take a 8.0 gram sample of substance A to decay such that only 1.
Fudgin [204]

Answer:

4.5

Explanation:

3 0
3 years ago
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