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pychu [463]
3 years ago
11

FREEEE POINTZZZZZZ Maybeee i'll mark brainliest toooooo. If u guys help figure out how to mark brainly

Chemistry
2 answers:
s344n2d4d5 [400]3 years ago
7 0

Answer:

thank you for the free points

Explanation:

Have a great day! I know  will, I'm gonna see my crush today... Anyhow have a good weekend! :)

chubhunter [2.5K]3 years ago
7 0

Thanks for the points. And have a good day!

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If 52500 J of heat is used to heat a 10200g block of metal and
Angelina_Jolie [31]

Answer:

45.95 Jkg^-1°C^-1

Explanation:

as specific heat capacity = heat energy / mass × delta

temperature

=52500/10.2×112

=45.95 Jkg^-1°C^-1

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3 years ago
Which identifies an oxidation-reduction reaction? a double replacement reaction a neutralization reaction a reaction in which ox
OLga [1]

A reaction in which oxidation numbers change is the answer! :D

☆ Dont forget to mark brainliest ☆

7 0
4 years ago
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Complete this sentence. The solubility of a sample will ____________ when the size of the sample increases.
slavikrds [6]
The solubility of a sample will DECREASE when the size of the sample increases.
The bigger a substance is, the more will be the particles that make up this substance and the greater the amount of solvent that will be needed to dissolve the substance. Surface area of the substance is also important, a small surface area will impede solubility. Thus, when the size of a sample increases, the solubility decreases.
5 0
3 years ago
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Consider the following reaction 2 N2O(g) => 2 N2(g) + O2(g) rate = k[N2O]. For an initial concentration of N2O of 0.50 M, cal
den301095 [7]

Answer:

After 2.0 minutes the concentration of N2O is 0.3325 M

Explanation:

Step 1: Data given

rate = k[N2O]

initial concentration of N2O of 0.50 M

k = 3.4 * 10^-3/s

Step 2: The balanced equation

2N2O(g) → 2 N2(g) + O2(g)  

Step 3: Calculate the concentration of N2O after 2.0 minutes

We use the rate law to derive a time dependent equation.

-d[N2O]/dt = k[N2O]

ln[N2O] = -kt + ln[N2O]i

 ⇒ with k = 3.4 *10^-3 /s

⇒ with t = 2.0 minutes = 120s

⇒ with [N2O]i = initial conc of N2O = 0.50 M

ln[N2O] = -(3.4*10^-3/s)*(120s) + ln(0.5)

ln[N2O] = -1.101

e^(ln[N2O]) = e^(-1.1011)

[N2O} = 0.3325 M

After 2.0 minutes the concentration of N2O is 0.3325 M

3 0
3 years ago
Hurry I need the answer asap
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Answer:

Heat or electricity in the atmasphere

Explanation:

4 0
2 years ago
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