Answer:
The molecular formule for this unknow molecule is C2H4O2
Explanation:
The empirical formula is CH2O ( or better said CnH2nOn)
This means there are 3 elements in the formula of this molecule
⇒ Carbon (C) with a Molar mass of 12 g/mole
⇒ Hydrogen (H) with a Molar mass of 1 g/mole
⇒ Oxygen (O) with a Molar mass of 16 g/mole
We can also notice that the amount of hydrogen should 2x the amount of carbon ( also 2x the amount of oxygen).
The mass of the empirical formule = 12g/ mole + 2* 1 g/mole + 16 g/mole = 30 g/mole
To know what number is n in CnH2nOn we should divide the molecular mass by the empirical mass:
60 g/mole / 30g/mole = 2
this means n = 2
and this will give a molecular formule of C2H4O2
We can control this to calculate the molecular mass:
2*12 + 4* 1 + 2*16 = 24 + 4 + 32 = 60 g/mole
The molecular formule for this unknow molecule is C2H4O2
Silver is A precious shiny grayish-white metal, the chemical element of atomic number 47. Silver is sometimes found in nature in metallic form. It forms a sulfide mineral Ag 2 S called acanthite. Mineral forms of silver include sulfides formed with antimony called Stephanite, miargyrite and pyrargyrite. Silver is a naturally occurring element on the periodic table and can be found in natural deposits throughout the world. As such, it was discovered in 5000 BC, but not invented, by people.
It’s oxidation number is +6
C. The number of moles of H in 0.109 mole of N₂H₄ is 0.436 mole
D. The number of moles of H in 34 moles of C₁₀H₂₂ is 748 moles
<h3>C. How to determine the number of mole of H in 0.109 mole of N₂H₄</h3>
1 mole of N₂H₄ contains 4 moles of H
Therefore,
0.109 mole of N₂H₄ will contain = 0.109 × 4 = 0.436 mole of H
<h3>D. How to determine the number of mole of H in 34 mole of C₁₀H₂₂</h3>
1 mole of C₁₀H₂₂ contains 22 moles of H
Therefore,
34 mole of C₁₀H₂₂ will contain = 34 × 22 = 748 mole of H
Learn more about mole:
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The mother liquor<span> is the part of a solution that is left over after it crystallizes. An example of a place you could find this is in sugar refinement.</span>