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3 years ago

How many atoms are in 6.30 moles of sulfur (S)?

Chemistry

1 answer:

STatiana [176]3 years ago

8 0

Answer: 3.79*10^24 atoms

Explanation:

1 mole = 6.02214076*10^23 atoms

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The reaction 2 ClO2(g) + F2(g) → 2 FClO2(g) is first-order in both ClO2 and F2. When the initial concentrations of ClO2 and F2 a

kupik [55]

Answer:

3. 75.0%

Explanation:

2 ClO2(g) + F2(g) → 2 FClO2(g)

First order with respect to ClO2 and F2.

This means the rate equation is given as;

Rate = k [ClO2][F2]

When the initial concentrations of ClO2 and F2 are equal?

Let's assume an initial value of 1 for both reactants, so rate equation is given as;

Rate = k * 1 * 1 = k

The rate after 25% of the F2 has reacted is what percent of the initial rate?

The concentration left of F2 is 75% ( 100% - 25%) = 0.75

Concentration of ClO2 remains 1.

So rate equation is given as;

Rate = k * 1 * 0.75 = 0.75 k

Comparing 0.75k and k.

This means our answer is;

3. 75.0%

6 0

3 years ago

HELPPPP PLEASEEEE Metal or Non-metal?

Tcecarenko [31]

Answer:

Fluorine:non-metal

Bromine:non-metal

Hydrogen:non-metal

Beryllium:metal

Nitrogen:non-metal

8 0

3 years ago

If 0.600mol of chloride gas reacted with 0.500mol of aluminium metal to produce aluminium chloride,which reactant is in excess?h

alisha [4.7K]

Answer:

собак гандонов в гавне))))))))))

Explanation:

hloride,which reactant is in excess?how many moles of aluminium chloride can be produced during the reaction.hloride,which reactant is in excess?how many moles of aluсиськижопыссиськасуксиськипись loride can be produced during the reaction.hloride,which reactant is in excess?how many moles of aluminium chloride can be produced during the reaction.hloride,whichйух reactant is in excess?how many moles of aluminium chloride can be produced during the reaction.

5 0

2 years ago

Calculate the atomic mass of lead. The four lead isotopes have atomic masses and relative abundances of 203.973 amu (1.4%), 205.

blondinia [14]

207.217 amu
Work:
203.973 amu *(0.014) = 2.855 amu
205.974 amu *(0.241) = 49.639 amu
206.976 amu *(0.221) = 45.741 amu
207.977 amu *(0.524) = 108.979 amu

2.855 + 49.639 + 45.741 + 108.979 = 207.217 amu

8 0

3 years ago

Santiago's car has an overall average speed of 25 cm/s. If he could increase his car's overall average speed by 10%, what would

Evgen [1.6K]

Given:

The overall average speed = 25 cm/s.

The overall average speed increased by 10%.

To find:

The new overall average speed.

Solution:

We have,

Overall average speed = 25 cm/s.

The overall average speed increased by 10%. So, the new average speed is

New overall average speed = Initial average speed + 10% of initial overall average speed

$\text{New overall average speed}=25+\dfrac{10}{100}\times 25$

$\text{New overall average speed}=25+2.5$

$\text{New overall average speed}=27.5$

Therefore, the new overall average speed is 27.5 cm/s.

3 0

3 years ago