Hello!
The pressure of the gas when it's temperature reaches 928 °C is 3823,36 kPa
To solve that we need to apply
Gay-Lussac's Law. It states that the pressure of a gas when the volume is left constant (like in the case of a sealed container like an aerosol can) is proportional to temperature. This is the relationship derived from this law that we use to solve this problem:
![P2= \frac{P1}{T1}*T2= \frac{103 kPa}{25}*928=3823,36 kPa](https://tex.z-dn.net/?f=P2%3D%20%5Cfrac%7BP1%7D%7BT1%7D%2AT2%3D%20%5Cfrac%7B103%20kPa%7D%7B25%7D%2A928%3D3823%2C36%20kPa)
Have a nice day!
Answer:
A reduction potential measures the tendency of a molecule to be reduced by taking up new electrons. ... Standard reduction potentials can be useful in determining the directionality of a reaction. The reduction potential of a given species can be considered to be the negative of the oxidation potential.
Explanation:
Answer:
![m=0.127g](https://tex.z-dn.net/?f=m%3D0.127g)
Explanation:
Hello,
In this case, for a first-order reaction, we can firstly compute the rate constant from the given half-life:
![k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{55.6s}=0.0125s^{-1}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7Bln%282%29%7D%7Bt_%7B1%2F2%7D%7D%20%3D%5Cfrac%7Bln%282%29%7D%7B55.6s%7D%3D0.0125s%5E%7B-1%7D)
In such a way, the integrated first-order law, allows us to compute the final mass of the substance once 10.0 minutes (600 seconds) have passed:
![m=m_0*exp(-kt)=230.0g*exp(-0.0125s^{-1}*600s)\\\\m=0.127g](https://tex.z-dn.net/?f=m%3Dm_0%2Aexp%28-kt%29%3D230.0g%2Aexp%28-0.0125s%5E%7B-1%7D%2A600s%29%5C%5C%5C%5Cm%3D0.127g)
Best regards.
Answer:
heat energy to keep you warm and light energy to be able to read your book
Explanation:
Answer:
the third one The orange color one
Explanation: