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8090 [49]
2 years ago
10

Can someone please help me how to write down the equation and get the answer?

Chemistry
2 answers:
EleoNora [17]2 years ago
7 0

\huge { \blue{\underbrace{\pink{\overbrace{\green{Answer}}}}}}

→ - 31,380° C

\bf \tt \: Use \:  \: the \:  \: formula

Q = MC∆T

where :

<em>Q </em>is heat energy, <em>m</em> is mass, <em>c </em>is specific heat, and ∆T is change in Temperature.

∆T\:  = T_{final} -  T_{initial}

\\ \bf \:  GIVEN : \\ \\ \:  \tt m \:  = 250g \\ \\   \:  \tt \: c =  \frac{4.184j }{g.c}  \\  \tt \:  T_{initial}  =95°C  \\  \tt  T_{final} =  65°C \\

∆T = 65°C - 95°C = – 30°C

\bf \: To \:  \: find : \\   \tt \: • Q \:

\bf \mathfrak { \blue{\underline{\green{solution}}}}:

\tt \:   Put \:  \: the \:  \: given \:  \: values \:  \: in \:  \: the \:  \: formula \\

  • Q = MC∆T

\tt \: Q\:  = (250g) (\frac{4.184 \: j}{g•°C} )( - 30°C) \\  \\  \:  \tt \:  =  >  - 31,380\: j\\  \\  \tt \: the \:  \: negative \:  \: signs \:  \: means \:  \: that \:  \: energy \\ \tt was \: \: released

Bumek [7]2 years ago
4 0

Answer:

<h3><u>E</u><u>Q</u><u>U</u><u>A</u><u>T</u><u>I</u><u>O</u><u>N</u><u>:</u></h3>

Measuring the Quantity of Heat

What Does Heat Do?

Measuring the Quantity of Heat

Calorimeters and Calorimetry

On the previous page, we learned what heat does to an object when it is gained or released. Heat gains or losses result in changes in temperature, changes in state or the performance of work. Heat is a transfer of energy.

<h3><u>S</u><u>H</u><u>O</u><u>W</u><u> </u><u>Y</u><u>O</u><u>U</u><u>R</u><u> </u><u>W</u><u>O</u><u>R</u><u>K</u><u>:</u></h3>

Specific Heat Capacity

Suppose that several objects composed of different materials are heated in the same manner. Will the objects warm up at equal rates? The answer: most likely not. Different materials would warm up at different rates because each material has its own specific heat capacity. The specific heat capacity refers to the amount of heat required to cause a unit of mass (say a gram or a kilogram) to change its temperature by 1°C. Specific heat capacities of various materials are often listed in textbooks.

Explanation:

<h3>please mark a brainliest myanswer please</h3>
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State whether the sign of the entropy change expected for each of the following processes will be positive or negative, and expl
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Answer:

a) ΔS is negative

b) ΔS is positive

c) ΔS is positive

d) ΔS is negative

Explanation:

Entropy (S) is a thermodynamic parameter which measures the randomness or the disorder in a system. Greater the disorder more positive will be the value of entropy.

The extent of disorder increases as substances transition from the solid to the gaseous state. i.e.

S(solid) < S(liquid) < S(gas)

The entropy change for a given reaction is:

\Delta S = S(products)-S(reactants)----(1)

a) PCl3(l) + Cl2(g) \rightarrow PCl5(s)

Here  the reactants are in the liquid and gas phase which have higher entropy than the product which is in the solid phase i.e. lower entropy.

Since S(product) < S(reactant), based on equation 1, ΔS will be negative.

b) 2HgO(s) \rightarrow 2Hg(l) + O2(g)

Here the products are in the liquid and gas phase which have higher entropy than the reactant which is in the solid phase i.e. lower entropy.

Since S(product) > S(reactant), based on equation 1, ΔS will be positive.

c) H2(g) \rightarrow 2H(g)

Here the products and reactants are in the gas phase. However the number of moles of products is greater than the reactants

Since S(product) > S(reactant), based on equation 1, ΔS will be positive.

d) U(s) + 3F2(g) \rightarrow UF6(s)

Here  one of the reactants is in the gas phase which corresponds to a more positive entropy compared to the  product which is in the solid phase i.e. lower entropy.

Since S(product) < S(reactant), based on equation 1, ΔS will be negative.

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Iodine gas in a container is heated over a flame. What happens to the average kinetic energy of the iodine particles
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Answer:

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2 years ago
Cyclobutane, C4H8, consisting of molecules in which four carbon atoms form a ring, decomposes, when heated, to give ethylene. Th
frosja888 [35]

Answer:

The concentration of cyclobutane after 875 seconds is approximately 0.000961 M

Explanation:

The initial concentration of cyclobutane, C₄H₈, [A₀] = 0.00150 M

The final concentration of cyclobutane, [A_t] = 0.00119 M

The time for the reaction, t = 455 seconds

Therefore, the Rate Law for the first order reaction is presented as follows;

\text{ ln} \dfrac {[A_t]}{[A_0]} = \text {-k} \cdot t }

Therefore, we get;

k = \dfrac{\text{ ln} \dfrac {[A_t]}{[A_0]}}  {-t }

Which gives;

k = \dfrac{\text{ ln} \dfrac {0.00119}{0.00150}}  {-455} \approx 5.088 \times 10^{-4}

k ≈ 5.088 × 10⁻⁴ s⁻¹

The concentration after 875 seconds is given as follows;

[A_t] = [A₀]·e^{-k \cdot t}

Therefore;

[A_t] = 0.00150 × e^{5.088 \times 10^{-4} \times 875}  = 0.000961

The concentration of cyclobutane after 875 seconds, [A_t] ≈ 0.000961 M

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