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slava [35]
3 years ago
11

Question 28 (4 points)

Chemistry
1 answer:
bixtya [17]3 years ago
6 0

Answer:

Pls type your question in another manner cos I really cant decipher what you wrote the way you typed this pls

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A student found the mass of the irregular solid to be 6.4 grams and the volume on the graduated cylinder rose from 6.8 mL to 7.7
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Density, Volume and Mass

3. A metal weighing 7.101 g is placed in a graduated cylinder containing 33.0 mL of water. The water

level rose to the 37.4 mL mark.

a) Calculate the density of the metal (in g/mL).

b) If you were to do this with an equal mass of aluminum (d = 2.7 g/mL), how high would the water rise?

7 0
3 years ago
A cube of steel has dimensions 0.2 mx 0.2 m * 0.2 m. What is
never [62]

Answer: 800”

Explanation:

5 0
3 years ago
Read 2 more answers
Draw the major addition product of the acid-catalyzed hydration of 4-ethyl-3,3-dimethyl-1-hexene.
kipiarov [429]

Here we have to draw the major product in the acid catalysed hydration reaction of 4-ethyl-3,3-dimethyl-1-hexene.

The 4-ethyl-3,3-dimethyl-1-hexene converts to 2-hydroxy-4-ethyl-3,3-dimethyl-1-hexane as a major product by acid catalyzed hydration reaction.  

The acid catalyzed hydration of an alkene is the Sn¹ reaction. Where in the first step a carbocation is generated. The stability of the carbocation depends upon the position of the neighboring group having +I inductive effect.

In the next step the water molecule attack the carbocation and the corresponding alcohol is produced.

In 4-ethyl-3,3-dimethyl-1-hexene the carbocation formed in the C₂ position which is more stable than the C₁ position due to presence of the dimethyl and ethyl group in the neighboring position which have strong +I inductive effect. This is absence in C₁ position.

In the next step the water molecule attack the C₂ position to form the alcohol.

4-ethyl-3,3-dimethyl-1-hexene converts to 2-hydroxy-4-ethyl-3,3-dimethyl-1-hexane by acid catalyzed hydration reaction which is the major product along with 1-hydroxy-4-ethyl-3,3-dimethyl-1-hexane as a minor product.

The reaction mechanism is shown in the image.          

7 0
3 years ago
Determine the empirical formula of the following compound if a sample contains 0.104 molK, 0.052 molC, and 0.156 molO.
Nadya [2.5K]

The empirical formula is K₂CO₃.  

The empirical formula is the <em>simplest whole-number ratio of atoms</em> in a compound.  

The ratio of atoms is the same as the ratio of moles, so our job is to calculate the <em>molar ratio of K:C:O</em>.  

I like to summarize the calculations in a table.  

<u>Element</u> <u>Moles</u>  <u>Ratio</u>¹ <u>Integers</u>²  

     K       0.104   2.00         2

     C       0.052  1.00          1

     O      0.156   3.00         3

¹ To get the molar ratio, you divide each number of moles by the smallest number.  

² Round off the number in the ratio to integers to integers (2, 1, and 3).

The empirical formula is K₂CO₃.

6 0
3 years ago
Which element will become an ion with a +2 charge
yKpoI14uk [10]
Magnesium atom


hope that helps!
4 0
3 years ago
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