During action potential, positively charged sodium ions move inside the cell.
So option D is correct one.
The sodium ion moves inside the cell during a action potential. The stage of action potential is called depolarization . This open voltage gated sodium channel.
Action potentials ( those electrical impulse that send signals around body ) is nothing but more than temporary shift ( from negative to positive ) in the neuron's membrane potential caused by ions suddenly flowing in and out of the neuron.
It consists of phases:
- Depolarization
- overshoot
- repolarization
An active potential propagates along the cell membrane of an axon until it reaches the terminal button.
to known more about action potential
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= 9.1 × 10^6
(scientific notation)
= 9.1e6
(scientific e notation)
= 9.1 × 10^6
(engineering notation)
(million; prefix mega- (M))
= 9100000
<span>(real number)</span>
For starters, I would get the same height for each paper, such as a counter top. Then, I would make said paper. You would use a timer of course, maybe even something like a speed gun to calculate the speed as said paper falls. You would push each paper off the counter top and calculate the speed for each paper. This is the easiest way to prove your hypothesis.
Answer and Explanation:
The options aren't listed in your question, but here are some units that are regularly and normally used (in the classroom and in the outside world):
(The SI unit of distance and displacement is the meter. The SI unit of time is the second.)
<u>Meters per Second (m/s)</u>
kilometers per hour (km/hr)
kilometers per second (km/sec)
To find the average speed, you do distance divided by time.
To find the average velocity, you do the final position minus the initial position, divided by the final time minus the initial time.
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<em><u>I hope this helps!</u></em>
Answer:
pH of resulting solution = 7.98
Explanation:
The balanced equation
HA + NaOH - Na+ + A- + H2O
Number of moles of A = Number of moles of HA = Number of moles of NaOH
= 35.8/1000 * 0.020 = 0.000716 mol
Initial concentration of A = 0.000716/0.0608 = 0.01178 M
pKb = 14 – pKa = 14 -3.9 = 10.1
Kb = 10^{-Kb} = 10^{-10.1} = 7.943 * 10^-11
Kb = [HA][OH-]/[A-]
Kb = a^2/(0.01178 -a) = 7.943 * 10^-11
a^2 + 7.943 * 10^-11 a – 9.357 * 10^-13 = 0
a = 9.673 * 10^-7
OH- = a = 9.673 * 10^-7 M
pOH = -log [OH-] = -log (9.673 * 10^-7) = 6.02
pH = 14-6.02 = 7.98
